Ask question

Ask question

All categories

1 year ago

6

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013. What was the mean amount of pr

ecipitation during this time? Round to the nearest hundredth.
A) 1.97 Inches
B) 2.61 Inches
C) 5.33 Inches
D) 5.98 Inches

2 answers:

polet [3.4K]1 year ago

7 0

Hello,
Please, see the attached file.
Thanks.

zhannawk [14.2K]1 year ago

5 0

Answer : C) 5.33 Inches

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013.

We are given with 9 values.

number of values =9

To find the mean amount of precipitation during this time we add all the precipitation then divide by number of values

$Mean amount of precipitation = \frac{Sum of precipitation}{number of values}$

$Mean amount of precipitation = \frac{5.98+6.05+7.59 +5.27+ 3.11+7.18+ 2.95 + 7.22+2.61}{9}$

= $\frac{47.98}{9} = 5.32888$

The mean amount of precipitation = 5.33 inches

You might be interested in

Given right triangle XYZ, what is the value of tan(60°)?

Svetlanka [38]

we know that

Step $1$

in the right triangle XYZ

Applying the Pythagorean Theorem

Find the value of ZY

$XY^{2}=XZ^{2} +ZY^{2} \\ ZY^{2}=XY^{2}-XZ^{2}\\ ZY^{2}=42^{2}-21^{2}\\ ZY^{2}=1,323\\ ZY=\sqrt{1,323}\ units$

$ZY=21\sqrt{3}\ units$

Step $2$

in the right triangle XYZ

Find tan $60$ °

we know that

$tan\ 60=\frac{opposite\ side\ angle\ 60}{adjacent\ side\ angle\ 60}$

in this problem

opposite side angle $60$ is ZY

adjacent side angle $60$ is XZ

so

$tan\ 60=\frac{ZY}{XZ} \\ \\ tan\ 60=\frac{21\sqrt{3}}{21} \\ \\ tan\ 60=\sqrt{3}$

therefore

the answer is

$\sqrt{3}$

3 0

1 year ago

Read 2 more answers

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

a

The 95% confidence interval is $0.0503 < p < 0.1297$

b

The sample proportion is $\r p = 0.09$

c

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

d

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

1 year ago

On zeba's birthday,her uncle gift her two new dolls. in how many ways can zeba arrange all her dolls on 6 shelves, placing one d

Natasha2012 [34]

Answer:

6 is the correct answer

Step-by-step explanation:

Hope it is helpful...

3 0

1 year ago

L = loudness, in decibels (dB); I = sound intensity, in watts/m2; I0 = 10−12 watts/m2

irina [24]

The sound intensity of the Pile Driver is 39.5
or nearly 40 times the sound intensity of the jackhammer.

Given with Loudness in dB for pile driver = 112 dB
We have to convert it in terms of sound intensity.
First,
112dB/10 = 11.2

Then we'll use this as exponent of 10
(10)^(11.2) = 1.5849 * 10 ^ 11

Then use the equation of Watts per square meter to find the intensity:
I / (10^-12 W/m^2) =1.5849 * 10 ^ 11
I = sound intensity = 0.158

Then compare:

Sound intensity of Pile Driver/ Sound intensity of Jackhammer
(0.158) / (0.004)
= 39.5
or nearly 40 times the jackhammer.

3 0

2 years ago

Read 2 more answers

In a certain mid-size city, 90% of the high- school graduates are from public schools and the other 10% are from private schools

trapecia [35]

The answer should be .53

8 0

1 year ago