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1 year ago

Which statements are true about the graph of the function f(x) = x2 - 8x + 5? Select three options.

Mathematics

1 answer:

Fofino [41]1 year ago

9 0

Answer:

the y-intercept is (0,5)

Step-by-step explanation:

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Point F is on circle C. What is the length of line segment GF? 12.5 units 15.0 units 17.5 units 20.0 units

geniusboy [140]

The answer:
According to the image, <span>the length of line segment GF can be found with
</span>GF= GC +CF
CF is one the radius, so CF=7.5
to find GC, we can apply Pythagorean theorem on the right triangle GEC
it is
GC² =GE² + EC² = 10² +7.5² =156.25, and then GC= sqrt(156.25)=12.5

therefore, GF= GC +CF=12.5+7.5=20

so the answer is <span>20.0 units</span>

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1 year ago

Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve

saw5 [17]

The correct answer for this problem is a. $39695. Hope this helps!

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1 year ago

Read 2 more answers

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

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1 year ago

A cake has a mass of 2.5kg. It contains 275g of fruit. What percentage of fruit is there in the cake

Travka [436]

The answer is: "11 %" .
__________________________________
There is 11% of fruit in the cake.
______________________________
Explanation:
____________________________________

275g is what percent of 2.5 kg?

First, convert "275 g" into "kg".

Note the exact conversion: 1000 g = 1 kg .

So 275 g = (275/1000) kg = 0.275 kg .

0.275 kg = (n/100) * 2.5 kg ;

→ (n/100) * 2.5 = 0.275 ;
____________________________
Divide each side by "(2.5)"
______________________
→ (n/100) = (0.275) / (2.5) ;

→ (n/100) = 0.11 ;

Multiply each side by "100" ;

n = 11 .
________________________________________
The answer is: 11 % .
________________________________________

8 0

1 year ago

Read 2 more answers

Zeke goes to a skate shop with his friend Tristan. Tristan buys a helmet that costs $28.75. Zeke finds a helmet that is <img src

Lemur [1.5K]

Answer: $2.75

Step-by-step explanation:

Zeke's helmet cost 3/5 x 28.75 = 17.25

Change = 20 - 17.25 = 2.75

4 0

1 year ago