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Elenna [48]
2 years ago
11

Zach uses his car for business and must keep accurate driving records so that his company will reimburse him for car expenses. W

hen he started his trip, the odometer read 26.645, When he returned home, the odometer read 28,017. Zach's car gets about 48 miles per gallon. If the tank was full at the beginning of the trip and it cost $62.28 to fill the tank at the end of the trip, what price did Zach pay per gallon?
Mathematics
1 answer:
Phoenix [80]2 years ago
7 0
His end mileage minus his starting mileage will give us the total number of miles he traveled.  28017-26645=1372 miles traveled.
We can divide that by his average mpg to figure out how many gallons of gas he bought:
1372/48 = 28.583 gallons.
Now divide the amount he paid by this to get the price per gallon:
62.28/28.583 = $2.179 per gallon of gas.
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P=1687.5/(0.09*10/12)
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5. Mrs. Jones is handing out candy to trick-or-
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 ANSWER. BBB

Step-by-step explanation:

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A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour what is the
vlabodo [156]
<span>A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is the train’s original speed?
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let x=original speed
x+5=increased speed
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..
lcd:x(x+5)
150(x+5)-150x=x(x+5)
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7 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
2 years ago
Find the perimeter of $\triangle CDE$ . Round your answer to the nearest hundredth. A trapezoid A B C D is plotted on a coordina
guapka [62]

Answer:

The answer is below

Step-by-step explanation:

We are asked to find the perimeter of triangle CDE. The perimeter of a shape is simply the sum of all its sides, hence:

Perimeter of tiangle CDE = |CD| + |DE| + |CE|

Given that C(4, -1), D(4, -5), E(2, -3).

The distance between two points X(x_1,y_1)\ and\ Y(x_2,y_2) is given as:

|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Therefore the lengths of the triangle are:

|CD|=\sqrt{(4-4)^2+(-5-(-1))^2} =4\ units\\\\|DE|=\sqrt{(2-4)^2+(-3-(-5))^2} =2.83\ units\\\\|CE|=\sqrt{(2-4)^2+(-3-(-1))^2} =2.83\ units

Perimeter of CDE = 4 + 2.83 + 2.83 = 9.66 units

8 0
2 years ago
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