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slamgirl [31]
1 year ago
15

A right prism has a rhombus as a base. the height of the prism is 6 inches and the volume is 144 cubic inches. which could be th

e lengths of the diagonals of the rhombus? 2 in. by 12 in. 4 in. by 11 in. 6 in. by 8 in. 8 in. by 9 in.
Mathematics
2 answers:
Crank1 year ago
8 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Volume of right prism = 144 cubic inches

Right prism has a rhombus as a base.

Height of the prism = 6 inches

As we know the formula for "Volume of right prism":

Volume=\text{Area of base}\times height\\\\144=\frac{1}{2}\times d_1\times d_2\times 6\\\\\frac{144\times 2}{6}=d_1\times d_2\\\\48=d_1\times d_2

By option we get that

lengths of diagonals could be 6 inches by 8 inches

∵ 8×6 = 48 in²

Hence, Third option is correct.

Alex1 year ago
5 0
The answer is C 6in by 8 in. 
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The image of \left[\begin{array}{c}4&-4\end{array}\right] through T is \left[\begin{array}{c}24&-8\end{array}\right]

Step-by-step explanation:

We know that T: IR^{2}  → IR^{2} is a linear transformation that maps e_{1} into y_{1} ⇒

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We can find the matrix A by applying T to a base of the domain (IR^{2}).

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Being B_{IR^{2}} the cannonic base of IR^{2}

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Writing the matrix A :

A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]

Now with the matrix A we can find the image of \left[\begin{array}{c}4&-4\\\end{array}\right] such as :

T(x)=Ax ⇒

T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]

We found out that the image of \left[\begin{array}{c}4&-4\end{array}\right] through T is the vector \left[\begin{array}{c}24&-8\end{array}\right]

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