Read the proof. Given: AB ∥ DE Prove: △ACB ~ △DCE We are given AB ∥ DE. Because the lines are parallel and segment CB crosses bo
th lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA. We can state ∠C ≅ ∠C using the reflexive property. Therefore, △ACB ~ △DCE by the AA similarity theorem. SSS similarity theorem. AAS similarity theorem. ASA similarity theorem.
2 answers:
Answer:
(A) AA similarity
Step-by-step explanation:
Given: AB is parallel to DE.
To prove: △ACB is similar to △DCE.
Proof: It is given that AB is parallel to DE, thus because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines.
Now, from △ACB and △DCE, we have
∠CED≅∠CBA (corresponding angles of transversal CB and are therefore congruent)
and ∠C ≅ ∠C (Reflexive property)
Thus, by AA similarity postulate,
△ACB is similar to △DCE
Hence proved.
Thus, option A is correct.
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The current rate is simply equal to $175 per month, let us call this as rate A:
A = 175
The new rate is $94 plus $4.50 per devices, let us call this as rate B:
B = 94 + 4.50 x
where x is the number of devices connected to the network
The inequality equation for us to find x which the new plan is less than current plan is:
94 + 4.50 x < 175
Solving for x:
4.50 x < 81
x < 18
So the number of devices must be less than 18.
- From the graph, we can actually see that the new rate intersects the current rate at number of devices equal to 18. So it should really be below 18 devices.
