Number > 5 - round up
Number = 5 - round up
Number < 5 - round and keep the number the same
7526.442
Hundredth = 2nd decimal place = 4
2 < 5
Round and keep the number the same
7526.44
Here we are given the specific equation of:
amount of eroded soil = 0.4 + 1.3 x
where x is the flow rate
A linear equation has a general formula in the form of:
y = m x + b
where m is the slope and b is the y intercept of the equation
If we compare this with our specific equation, we can see that the slope and y intercept are both positive with values:
m = 0.4
b = 1.3
Therefore this only means that as the flow rate increases, the amount of eroded soil also increases.
Hence the correlation must be positive but we cannot solve for the exact value since we need the data for x and y.
Answer:
positive, but we cannot say what the exact value is
To find the answer to this question, you simply find the greatest common factor.
All of these numbers have many factors, like 1, 2, 3, 4, and 6.
The greatest common factor is 12.
36, 48, and 60 can all be divided by 12 with no leftover or decimals. There is no higher common factor.
The maximum number of bowls she can put the items into is 12 bowls.
I hope this helps :)
Your new total would be 177.5 because if you add the past due balance and add the charge of $75 and then add the 15% late fee you would get 177.5
87.50 + $75 + 15% = 177.5
Hopefully this right, if it is not i am so very sorry, Have a Good Evening:) ~Nana~!
Answer: (a) 4
(b) 5
(c) 14
(d)
Class interval Class mark
30 - 35 
35 - 40 
40 - 45 
45 - 50 
50 - 55 
Step-by-step explanation:
The data of 40 persons is given as :
Weights (in kg) Frequency
30 - 35 6
35 - 40 13
40 - 45 14
45 - 50 4
50 - 55 3
(a)
<em>Lower limit is the lowest number in a class interval .</em>
So, is the lower limit of fourth-class interval (45 - 50) is 4.
(b)
<em>Class size = Upper limit - lower limit </em>
So, Class size of first class interval = 35-30=5
Thus , class size of each interval is 5. [ class size remains same]
(c)
Highest frequency in table = 14 which is corresponding to 40 - 45 .
Thus , 40 - 45 is the class interval has the highest frequency.
(d)
<em>Class mark is the mid value of each class interval.</em>
<em>Class interval = </em>
Class interval Class mark
30 - 35 
35 - 40 
40 - 45 
45 - 50 
50 - 55 