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2 years ago

Write 11,760,825 in word form and expanded form

1 answer:

5 0

11,000,000 + 700,000 + 60,000 + 800 + 20 + 5 (expanded form)

eleven million seven hundred sixty thousand eight hundred twenty-five (word form)

You might be interested in

Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete

bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

$\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}$

b) 19 inches and 50 inches

$\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}$

c) 33 centimeters and 80 centimeters

$\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}$

Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.

6 0

2 years ago

Two standard dice are rolled and their face values multiplied. What is the probability that the product is prime or ends in 0?

Trava [24]

The answer is 10/36 or 27.77%
here’s the working out

8 0

2 years ago

A train is leaving in 11 minutes and you are one mile from the station. Assuming you can walk at 4mph and run at 8mph, how much

ddd [48]

7 minutes is the time can you afford to walk

Solution:

Given that, train is leaving in 11 minutes and you are one mile from the station

Let "x" represent how much time can you afford to walk

Then, (11 - x) is the time you run

You can walk at 4mph and run at 8mph

Convert to miles per minute

1 hour = 60 minutes

$4\ mph = 4 \times \frac{1}{60} \text{ miles per minute } = \frac{1}{15} \text{ miles per minute }\\\\8\ mph = 8 \times \frac{1}{60}\ \text{ miles per minute } = \frac{2}{15} \text{ miles per minute }$

We know that,

$Distance = speed \times time$

Given that, you are one mile from the station

Therefore,

1 mile = distance walk + distance run

$1 = x \times \frac{1}{15} + (11-x) \times \frac{2}{15}\\\\1 = \frac{1}{15}(x + 2(11-x))\\\\1 = \frac{1}{15}(x + 22 - 2x)\\\\x + 22 - 2x = 15\\\\x = 22 - 15\\\\x = 7$

Thus, 7 minutes is the time can you afford to walk

6 0

2 years ago

Find the upper bound for 96.3cm measured to the nearest tenth of a cm

Zarrin [17]

Answer:

100cm

Step-by-step explanation:

Will be 100cm as when approximated to tenth

Tenth of cm or any other measure it must ends with 10 or zeroz digit that is 20,30 or 97be 100

8 0

2 years ago

The sequence 6, 18, 54, 162, … shows the number of pushups Kendall did each week, starting

Andrei [34K]

a) The given sequence is geometric.

b) The next term in the sequence is 486

c) The rule is: $a_n=6(3)^{n-1}$

The 20th week will be: a_{20}=6973568802

Step-by-step explanation:

The sequence 6, 18, 54, 162, … shows the number of push ups Kendall did each week, starting with her first week of exercising.

Part a) Is this an arithmetic or geometric sequence?

An arithmetic sequence is one, where difference between two consecutive terms is constant.

In the given sequence 6, 18, 54, 162,

18-6 = 12

54-18= 36

The difference is not constant so, the sequence is not arithmetic.

A geometric sequence is one, where ratio between two consecutive terms is constant.

In the given sequence 6, 18, 54, 162,

18/6 = 3

54/18 = 3

162/54 = 3

The ratio is constant so, the sequence is geometric.

The given sequence is geometric.

Part b) How can you find the next number in the sequence?

We can find next number in the sequence by using formula:

$a_n=a(r)^{n-1}$

where a_n= nth term

a= first term

r= common ratio

The next term will be 5th term of the sequence.

Finding 5th term:

$a_n=a(r)^{n-1}\\a_5=6(3)^{5-1}\\a_5=6(3)^4\\a_5=6*81\\a_5=486$

So, the next term in the sequence is 486

Part c) Give the rule you would use to find the 20th week. Find the 20th week

The rule used to find 20th week would be:

$a_n=6(3)^{n-1}$

Here n=20

Finding 20th week

$a_n=6(3)^{n-1}\\a_{20}=6(3)^{20-1}\\a_(20)=6(3)^{19}\\a_{20}=6973568802$

5 0

2 years ago