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2 years ago

Write 11,760,825 in word form and expanded form

1 answer:

5 0

11,000,000 + 700,000 + 60,000 + 800 + 20 + 5 (expanded form)

eleven million seven hundred sixty thousand eight hundred twenty-five (word form)

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A surveyor measures the length of a surveying chain containing 1000 chain links. The length is 0.0533km. What is the length of a

Leya [2.2K]

Answer:

length of a single chain link = 5.33 cm

Step-by-step explanation:

Given data: chain contained 1000 chain links

total length was 0.0533km

1km = 1000m

1m = 100cm therefore 1km = 100000cm

total length in cm = 0.0533* 100000

total length in cm = 5330 cm

length of a single chain link = 5330/1000

length of a single chain link = 5.33 cm

7 0

2 years ago

Eileen makes her own granola using 1 3/4 cups of oats and 2/3 cup of puffed rice. How many cups of granola does she have?

barxatty [35]

Answer:

2 5/12 cups

Step-by-step explanation:

First, turn 1 3/4 into improper fraction:

1 3/4 = 7/4

Next, Find LCG (least common multiple) of 3 and 4

Multiples of 4: 4, 8, 12, 16, 20, 24

Multiples of 3: 3, 6, 9 , 12, 15, 18

Multiply 7/4 by 3 and 2/3 by 4

7/4 x 3 = 21/12

2/3 x 3 = 8/12

Add both fractions

21/12 + 8/12 = 29/12

Reduce 29/12

29/12 = 2 5/12

So Eileen has 2 5/12 cups of granola

Hope this helps ;)

4 0

2 years ago

A toy airplane climbs 30 vertical feet while traveling 50 feet horizontally. A toy helicopter climbs 20 feet while traveling 40

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

7 0

1 year ago

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

masha68 [24]

Well the sides of these 2 quadrilaterals are proportional to each other , so you would have to find the scale factor of the 2 then see which sides have already proportional pairs , then multiply *or / to find the last one .

Answer: D. 11.7 ft

5 0

2 years ago

Read 2 more answers

Fifty specimens of a new computer chip were tested for speed in a certain application, along with 50 specimens of chips with the

Murljashka [212]

Answer:

Under 99% confidence level we can say that mean speed of the new chips is greater than that of the old chips

Step-by-step explanation:

$H_{0}$ : Mean speed of the new chip is the same as the old chip

$H_{a}$ : Mean speed of the new chip is greater than the old chip

to calculate the z-statistic we can use the formula:

z= $\frac{M_{n}-M_{o}}{\sqrt{\frac{s_{n}^2}{N_{n}} +\frac{s_{o}^2}{N_{o}} } }$

if we put the numbers then

z= $\frac{495.6-481.2}{\sqrt{\frac{19.4^2}{65}} +\frac{14.3^2}{65} } }$ =4.8171

The probability of this z-statistic is < 0.001 Therefore Under 99% confidence level we can say that mean speed of the new chips is greater than that of the old chips

4 0

2 years ago