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2 years ago

When using the formula zx = x − μ σ for the z-score for the 11.7 data point:

Mathematics

2 answers:

Elodia [21]2 years ago

8 0

1. x= 11.7 μ = 7

2. z11.7= 1.3

3. Is 11.7 within a z-score of 3?

a. Yes because z11.7 < 3.

4. Which statement is true of z11.7?

b. z11.7 is between 1 and 2 standard deviations of the mean.

Margaret [11]2 years ago

6 0

Answer:

The z11.7 is actually 1.3 that's the answer I got and it said it was right. Hope this helps!

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Suppose an exponential function is fit to a set of data. Which of the following residual plots indicates that this function was

Zina [86]

The correct answer is the choice that you have selected, the third choice.

When, we are looking at the residuals for a regression line, we always want to see the points balance like in the third choice. This means that the equation that we found is right in the middle of the points.

7 0

1 year ago

Read 2 more answers

Mrs.Steﬀen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin

qaws [65]

Answer:

a. $\\ 10! = 3628800$ ;

b. $\\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}$

Step-by-step explanation:

We need here to apply the Multiplication Principle or the Fundamental Principle of Counting for each answer. Answer b needs an extra reasoning for being completed.

The Multiplication Principle states that if there are n ways of doing something and m ways of doing another thing, then there are n x m ways of doing both (Rule of product (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are ten students. When one is selected, there is no other way to select it again. So, no repetition is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is why the Multiplication Principle is important here.

This could be expressed mathematically using n!:

$\\ n! = n * (n-1)! * (n-2)! *...* 2*1.$

For instance, $\\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.$

So, for the case in question, the ten students can line up in:

$\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800$ ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy only the following places in forming the file:

$\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th}$ places.

The members of Group 2 only:

$\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th}$ places.

And the members of Group 3, the following only ones:

$\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th}$ places.

Well, having into account these possible places for each member of G1, G2 and G3, there are: 10! ways for lining up members of G1; 10! ways for lining up members of G2 and, also, 10! ways for lining up members of G3.

After using the Multiplication Principle, we have, thus:

$\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19}$ ways the students can line up to come in from recess.

3 0

1 year ago

Suppose that in a survey of 1,000 U.S. residents, 721 residents believed that the amount of violent television programming had i

Art [367]

Answer: 0.813

Step-by-step explanation:

Let A be the event describes the number of residents believed that the amount of violent television programming had increased over the past 10 years.

& B be the event describes the number of residents believed that the amount of violent television programming had decreased over the past 10 years.

Given : n(A)=721 ; n(B)=454 ; n(A∩B)=362

We know that ,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

i.e. $n(A\cup B)=721+454-362=813$

Also, the total number of U.S. residents surveyed n(S)= 1,000

Then, the proportion of the 1,000 U.S. residents believed that either the amount of violent programming had increased or the overall quality of programming had decreased over the past 10 years will be :-

$P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}=\dfrac{813}{1000}=0.813$

Hence, the required answer = 0.813

3 0

1 year ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$