Answer:
$45.12
Step-by-step explanation:
($0.47 /stamp)×(8 stamps/mo)×(12 mo/yr) = $45.12 /yr
You will save $45.12 per year on stamps.
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
Answer:
The simplified sum of these polynomials is 3x^4y - 2xy^5
Step-by-step explanation:
In order to find this, we need to remember that we can only add together like terms in this case, there are only two like terms. Both of the first terms end in x^2y^2. So, we add these two together.
3x^2y^2 - 3x^2y^2 = 0
Since they cancel out, we simply just put the other two terms as our answer.
3x^4y - 2xy^5
Answer:
A. The vector goes from (4, 0) to (3, -2).
Step-by-step explanation:
The tail of the vector is on the point (4, 0). The head of the vector is on the point (3, -2). Only answer choice A correctly identifies both of the points associated with the vector.
Answer:
Step-by-step explanation:
Find the digram attached.
Perimeter of the track = perimeter of the rectangle + perimeter of the 2semicircles
Perimter of a rectangle = 2(x+r) where:
x is the length
2r is the width of the rectangle = diameter of the semicircle
Perimeter of semicircle = 2πr/2 = πr
Perimeter of 2semicirle = 2πr
Perimeter of the track = 2(x+2r) + 2πr
r is the radius if the semicircle
Expand
Perimeter of the track = 2x+4r + 2πr
Perimeter of the track = 2(x+2r+πr)
b) Given P = 2(x+2r+πr), we are to make x the subject of the formula.
P = 2x+4r+2πr
P-4r-2πr = 2x
Divide both sides by 2.
(P-4r-2πr)/2 = 2x
x = (P-4r-2πr)/2
c) Given
P = 600fr
r = 50ft
x = (600-4(50)-2π(50))/2
x = (600-200-100(3.14))/2
x = 400-314/2
x = 86/2
x = 43ft
Hence the value of x to nearest foot is 43ft
