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LuckyWell [14K]
2 years ago
15

Rachel lives in a home with a value of $195,000 and has a mortgage of $160,000. She has electronic equipment worth $2,325. She i

s paying off the equipment with a loan of $875. Her car, which she owns, is worth $9,300. She has $6,890 in a bank account and $1,437 on her credit card. She owes $4,800 in student loans. She has a piano worth $1,200. Construct a net worth statement to find Rachel's net worth
Mathematics
1 answer:
Elan Coil [88]2 years ago
4 0

To Find :

Net worth of Rachel.

Solution :

Net worth is given by the (sum of all the assets she owns) -( total amount of loans she have ).

Net \ Worth=( 195000+160000+2325+9300+1437+1200)-(875+4800)\\\\Net \ Worth=\$\ 363587

Therefore, net worth of Rachel is $ 363587.

Hence, this is the required solution.

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The mean number of students in a classroom at school a is 32.5 and there are 25 classrooms. The mean number of students at schoo
Airida [17]

We have given three school there, School A, School B and School C.

We are going to use following formula.

Total number of student in a school = Mean of number of student × Number of classrooms.

School A

Mean of students in School A = 32.5.

Number of classroom in School A = 25.

Number of students in School A = Mean × number of classrooms = 32.5×25 = 812.5


School B

Mean of students in School B = 29.6.

Number of classroom in School B = 12.

Number of students in School B = Mean × number of classrooms = 29.6×12 = 355.2


School C

Mean of students in School C = 15.3.

Number of classroom in School C = 10.

Number of students in School C = Mean × number of classrooms = 15.3×10 = 153.


Total sum of number of classes in all schools = 25+12+10 = 47.

Total sum of all students in all schools = 812.5 +355.2 +153 = 1320.7 .

The mean number of students per classroom for all the schools combined =

\frac{Total \ sum \ of \ all \ students \ in \ all \ schools}{Total \ sum \ of \ number \ of \ classes \ in \ all \ schools}

= \frac{1320.7}{47} = 28.1

The mean number of students per classroom for all the schools combined= 28.1

4 0
2 years ago
There are two misshapen coins in a box; their probabilities for landing on heads when they are flipped are, respectively, .4 and
Leokris [45]

Answer:

E(X) = 6.0706

Step-by-step explanation:

1) Define notation

X = random variable who represents the number of heads in the 10 first tosses

Y = random variable who represents the number of heads in range within toss number 4 to toss number 10

And we can define the following events

a= The first coin has been selected

b= The second coin has been selected

c= represent that we have 2 Heads within the first two tosses

2) Formulas to apply

We need to find E(X|c) = ?

If we use the total law of probability we can find E(Y)

E(Y) = E(Y|a) P(a|c) + E(Y|b)P(b|c) ....(1)

Finding P(a|c) and using the Bayes rule we have:

P(a|c) = P(c|a) P(a) / P(c) ...(2)

Replacing P(c) using the total law of probability:

P(a|c) = [P(c|a) P(a)] /[P(c|a) P(a) + P(c|b) P(b)] ... (3)

We can find the probabilities required

P(a) = P(b) = 0.5

P(c|a) = (3C2) (0.4^2) (0.6) = 0.288

P(c|b) = (3C2)(0.7^2) (0.3) = 0.441

Replacing the values into P(a|c) we got

P(a|c) = (0.288 x 0.5) /(0.288x 0.5 + 0.441x0.5) = 0.144/ 0.3645 = 0.39506

Since P(a|c) + P(b|c) = 1. With this we can find P(b|c) = 1 - P(a|c) = 1-0.39506 = 0.60494

After this we can find the expected values

E(Y|a) = 7x 0.4 = 2.8

E(Y|b) = 7x 0.7 = 4.9

Finally replacing the values into equation (1) we got

E(Y|c) = 2.8x 0.39506 + 4.9x0.60494 = 4.0706

And finally :

E(X|c) = 2+ E(Y|c) = 2+ 4.0706 = 6.0706

6 0
2 years ago
Bob has five times as much money as John and together they have 60.00 what would this look like as an equation
Vanyuwa [196]
The equation would look like 60 = 5x
6 0
2 years ago
. A condo in Orange Beach, Alabama, listed for $1.4 million with 20% down and financing at 5% for 30 years. What is the monthly
vovikov84 [41]
Listed price = $1.4 million
Down payment = 20% of $1.4 million = 0.2 x 1,400,000 = 280,000
Amount left to pay = $1.4 million - 280,000 = $1,120,000
Present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt) / r
where: PV = $1,120,000
r = 5% = 0.05
t = 12
n = 30 years.
1,120,000 = P(1 - (1 + 0.05/12)^-(12 x 30)) / 0.05
1,120,000 x 0.05 = P(1 - (1 + 1/240)^-360)
56,000 = P(1 - 0.2238)
P = 56,000 / 0.7761 = 72,148.83
Therefore, the monthly payment is $72,148.83
8 0
2 years ago
a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b
AveGali [126]
No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.
5 0
2 years ago
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