Question

Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let x represent the price per pound for grapefruit, and let y represent the price per pound for oranges. Choose the system of equations that models the situation.

Answer 1

Answer: $\left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.$

Step-by-step explanation:

Let be "x"  the price per pound for grapefruit, "y" the price per pound for oranges.

We know that Steve buys 2 pounds of grapefruit and 3  of oranges for $7.20.

This means that the sum of the products of $2x$ and $3y$ is $7.20. Then, we can write this equation to represent it:

$2x+3y=7.20$

Kennedy buys 4 pounds of grapefruit and 2 pounds of oranges for $8.80.

This means that the sum of the products of $4x$ and $2y$ is $8.80. Then, we can write this equation to represent this:

$4x+2y=8.80$

Therefore, we get that the system of equations that models the situation is:

$\left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.$