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makkiz [27]
2 years ago
6

Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee

n the sides a and b of ∆ABC is more than 90°? area of square c2 = -area of square a2 − area of squareb2 + area of defect1 + area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 − area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 area of square c2 = area of square a2 − area of squareb2 + area of defect1 − area of defect2
Mathematics
1 answer:
horrorfan [7]2 years ago
4 0
Asked and answered elsewhere.
brainly.com/question/1410592

_____
Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
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A bank account earned 3.5% continuously compounded annual interest. After the initial deposit, no deposits or withdrawals were m
aalyn [17]

This question is incomplete. Below is the complete question:

A bank account earned 3.5% continuously compounded annual interest. After the initial deposit, no deposits or withdrawals were made. At the end of an 8 year period, the balance in the account was $13231.30. what is the amount of the initial deposit?

Answer: The initial deposit is $10,001

Step-by-step explanation:

To solve this we need to utilize the continuous compounding interest formula:-

Fv = Pv × e^(i × t)

Where, Fv = the future value

Pv = present value

i = the interest rate

t = the time in years

e = a mathematical constant that is usually approximated by 2.7183

In this case, the Fv = 13,231.30

i = 3.5% or 0.035

t = 8 years

e = 2.7183

Pv = ? (The unknown variable).

13,231.30 = Pv × [2.7183^(0.035 × 8)]

13,231.30 = Pv × [2.7183^(0.28)]

13,231.30 = Pv × 1.323

Pv = 13,231.30/1.323

Pv = $10000.98

= $10,001

Therefore the initial deposit is $10,001

8 0
1 year ago
Cameron wondered if the average score on a final exam was different between those who texted on a regular basis during the lectu
Margarita [4]

Answer:

c. A two-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

Step-by-step explanation:

Let p1 be the average score on a final exam who texted on a regular basis during the lectures for a particular class

And p2 be the average score on a final exam who did not texted at all during the lectures for a particular class

According to the Cameron's point of interest, null and alternative hypotheses are:

H_{0}: p1 = p2

H_{a}: p1 ≠ p2

Two tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

3 0
2 years ago
The diagram shows JKL. Which term describes point M?
laiz [17]

Answer:

A; Orthocenter

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
A rectangular field is enclosed by 360 feet of fencing. What is the length, in feet, of the field if it’s length is 6 feet more
Orlov [11]

Answer:

The Field's length is 93ft

Step-by-step explanation:

P=2L+2w

360=2(w+6)+2w

360=2w+12+2w

360=4w+12

348=4w

348/4=w

87=w

L=w+6

L=87+6

L=93

7 0
2 years ago
Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was \$43.25$43.25dollar sign, 43,
Elodia [21]

Answer:

29 minutes

Step-by-step explanation:

Given

Total = \$43.25

Entrance\ Fee = \$7

Per\ Minute = \$1.25

Required

Determine the number of minutes (t) that he was on the trampoline.

This can be expressed as:

Total\ Payment = Entrance\ Fee + Amount\ per\ minute * t

Where t represents the number of minutes

Substitute values for Total, Entrance Fee and Amount per minute

43.25 = 7 + 1.25 * t

43.25 = 7 + 1.25t

Solving further to get the value of t, we have:

1.25t = 43.25 - 7

1.25t = 36.25

t = 36.25/1.25

t = 29

3 0
2 years ago
Read 2 more answers
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