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makkiz [27]
2 years ago
6

Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee

n the sides a and b of ∆ABC is more than 90°? area of square c2 = -area of square a2 − area of squareb2 + area of defect1 + area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 − area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 area of square c2 = area of square a2 − area of squareb2 + area of defect1 − area of defect2
Mathematics
1 answer:
horrorfan [7]2 years ago
4 0
Asked and answered elsewhere.
brainly.com/question/1410592

_____
Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
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Transversal t cuts parallel lines a and b as shown in the diagram. Which equation is necessarily true?. a) m<1=m<2. b)m&lt
e-lub [12.9K]
M<1≠m<2
m<4≠m<6
m<3 + m<5 = 180° ≠ 90°
m<7≠m<8
Answer:
none of them.
7 0
2 years ago
Read 2 more answers
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
2 years ago
Which equation combines with the given equation to form a system of equations with the solution x = 3 and y = 9? x + 2y = 21
max2010maxim [7]
Yes. x=3 and y =9 are the solutions.
 Because if you change x=3 and y =9 ,you will have 
3+2* 9 =21
3+18 =21
21 =21 (true)
6 0
2 years ago
Read 2 more answers
A food company originally sells cereal in boxes with dimensions 25 cm by 14 cm by 10 cm. To make more profit, the company decrea
hjlf

Answer:

1.75 cm

Step-by-step explanation:

We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.

Now, to increase the profit, the dimensions of the box by 'x' cm.

Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.

Further, it is given that the volume of the new box is 2,208 cm^{3}

As, Volume of the box = Length × Breadth × Height

i.e. 2208 = (25-x) × (14-x) × (10-x)

i.e. 2208 = (25-x) \times (140-24x-x^{2})

i.e. 2208=x^{3}-x^{2}-740x+3500

i.e. x^{3}-x^{2}-740x+1292=0

On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.

Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.

Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.

Hence, the dimensions were decreased by 1.75 cm.

3 0
2 years ago
Luis made 80% of what he made last week.If he made 72$ this week,how much did he make last week
IceJOKER [234]

Let

x--------> the amount in dollars that Luis make last week

we know that

80\% =\frac{80}{100}=0.80

0.80x=72\$ ------> equation that represent the situation

solve for x

Divide by 0.80 both sides

0.80x/0.80=72\$/0.80

x=72\$/0.80

x=90\$

therefore

<u>the answer is</u>

90\$

4 0
2 years ago
Read 2 more answers
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