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Vera_Pavlovna [14]
1 year ago
6

Luis made 80% of what he made last week.If he made 72$ this week,how much did he make last week

Mathematics
2 answers:
ivann1987 [24]1 year ago
7 0

Answer:

He made $90 last week

Step-by-step explanation:

Since we are told that Louis made 80% of what he made last week and since Louise made $72 this week, to get how much he made this week, we will follow the step below:

let x be the amount he made last week

80% of x = $72

80% ×  x = $72

\frac{80x}{100}  = $72

the fraction 80x/100 can be reduced to 4x/5. Hence;

\frac{4x}{5}  = $72

Multiply both-side of the equation by 5

\frac{4x}{5}  x 5 = $72 x 5

4x =360

Divide both-side of the equation by 4 to get the value of x

\frac{4x}{4}  = \frac{360}{4}

On the left-hand side of the equation 4 will cancel-out 4 while on the right-hand side of the equation 360 will be divided by 4

x = $90

Therefore he made $90 last week

IceJOKER [234]1 year ago
4 0

Let

x--------> the amount in dollars that Luis make last week

we know that

80\% =\frac{80}{100}=0.80

0.80x=72\$ ------> equation that represent the situation

solve for x

Divide by 0.80 both sides

0.80x/0.80=72\$/0.80

x=72\$/0.80

x=90\$

therefore

<u>the answer is</u>

90\$

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A daycare made $40 during their first month in business. They doubled the amount of money they earned each month. What is the to
AfilCa [17]

Answer:

$81,920

Step-by-step explanation:

money made by january: $40

double that

money made by february: $80

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money made by april: $320

double that

money made by may: $640

double that

money made by june: $1,280

double that

money made by july: $2,560

double that

money made by august: $5,120

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money made by september: $10,240

double that

money made by october: $20,480

double that

money made by november: $40,960

double that

money made by december: $81,920

the total money they made by the end of the year (december) was $81,920

6 0
2 years ago
Read 2 more answers
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

7 0
2 years ago
Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o
Mazyrski [523]

Answer:

13

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

8 0
1 year ago
ALGEBRA 2/ TRIG QUESTION ATTACHED Please help ❤️❤️
ss7ja [257]
Let's calculate the value of angle A and B

sin(A) =-4/5 → sin⁻¹(- 4/5) = A  →  A = - 53.13


cos(B) = -5/13 → cos⁻¹ (- 5/13) = B  → B = 112.62


tan (A+B) = sin(A+B)/cos(A+B)  with A+B = -53.13 + 112.62 = 59.49

tan (A+B) = sin(59.49)/cos(59.49) = 0.86154/0.507688 = 1.6969.

(Answer H = 56/33 = 1.6969)

7 0
2 years ago
Choose the product. -7p 3(4p 2 + 3p - 1)
DIA [1.3K]

Answer:

14p -3

Step-by-step explanation:

-7p 3(4p 2+3p - 1)

3x4= 12p

3x3=9p

12+9= 21

21-7=14p

3x2=6

3x-3=-9

-9 +6= -3

= 14p -3

hope this helps :)

7 0
1 year ago
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