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Molodets [167]
2 years ago
12

The list shows the area in square feet of each apartment available for rent in a building. 565, 961, 867, 517, 627, 714, 517, 72

8 What is the range of these areas in square feet?
Mathematics
2 answers:
gladu [14]2 years ago
8 0
STEP 1:
put numbers in order from lowest to highest
517, 517, 565, 627, 714, 728, 867, 961

STEP 2:
find the difference between the lowest and highest numbers

961 - 517= 444 ft^2 range

ANSWER: The range of the areas is 444 ft^2.

Hope this helps! :)
garik1379 [7]2 years ago
4 0
The range of the areas is 444 feet squared
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Q#1:The volume of a cube is 46656 cubic metres.Find the length of each side?
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Answer:

Step-by-step explanation:

1) To find the cube root of a number prime factorize

46656 = 2*2*2*2*2*2 * 3 * 3 * 3 * 3 * 3 * 3

\sqrt[3]{46656}=\sqrt[3]{2*2*2*2*2*2*3*3*3*3*3*3}  =2*2*3*3 = 36

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1 year ago
A total of d dollars was donated to 4 charities. Each charity received $375. Which equation can be solved to find the total amou
lidiya [134]

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$375 x 4 = d

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2 years ago
Which polynomial function has a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1?
svlad2 [7]

Answer:

C. f(x)=(x-(7-i))(x-(5+i))(x-(7+i))(x-(5-i))

Step-by-step explanation:

We want to find the equation of a polynomial the following properties;

i. Leading coefficient is 1

ii. roots (7 + i) and (5 – i) with multiplicity 1

Recall the complex conjugate properties of the roots of a polynomial.

According to this property, if

a+bi is a root of a polynomial, then the complex conjugate, a-bi  is also a root.

This means that:

(7 - i) and (5 + i) with multiplicity 1 are also roots of this polynomial.

The complete set of roots are:

x=(7+i),x=(7-i),x=(5-i),x=(5+i)

Therefore the polynomial is:

f(x)=(x-(7-i))(x-(5+i))(x-(7+i))(x-(5-i))

The correct choice is C.

3 0
2 years ago
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In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?
vaieri [72.5K]

Answer:

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And  Cos B = \frac{CB}{AB}.

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

                               Hypotenuse = AB\\Base = CB\\Perpendicular = AC

So,                            Sin\theta = \frac{perpendicular}{hypotenuse}

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Then,                    CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

Hence,

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

                               

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2 years ago
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