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Akimi4 [234]
2 years ago
5

Marshall's mother buys 2 boxes of granola bars each week. Each box contains 8 granola bars. If she continues buying 2 boxes each

week, how many granola bars will she buy in a year (1 year = 52 weeks)?
Mathematics
1 answer:
frutty [35]2 years ago
7 0
2 x 8 =16
16 granola bars a week 
52 x 16 = 832 granola bars in a year
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A brochure from the department of public safety in a northern state recommends that motorists should carry 12 items (flashlights
scoray [572]

Answer:

Mean = 6.07

Median = 7

Mode = 7

Step-by-step explanation:

Given

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

n = 15

Solving (a): The mean

Mean is calculated as:

Mean = \frac{\sum x}{n}

This gives:

Mean = \frac{5+ 3+ 7+ 8+ 0+ 1+ 0+ 5+ 12+ 10+ 7+ 6+ 7+ 11+ 9}{15}

Mean = \frac{91}{15}

Mean = 6.07

Solving (b): The median

Sort the data in ascending order:

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

Sorted: 0\ 0\ 1\ 3\ 5\ 5\  6\ 7\ 7\ 7\ 8\ 9\ 10\ 11\ 12

The median is:

Median = \frac{n + 1}{2}th

Median = \frac{15 + 1}{2}th

Median = \frac{16}{2}th

Median = 8th    

The 8th item on the sorted dataset is 7; So:

Median = 7

Solving (c): The mode

Mode = 7

Because it has a frequency of 3 (more than any other element of the dataset).

6 0
2 years ago
Jenny bought a new car for $25,995. The value of the car depreciates by 16 percent each year. Which type of function could model
motikmotik

Answer: The answer is expensive the car is expensive. JK the answer is c. you can eliminate a and d because the 16 % a year increase so your left with c and b it's not b because of the price so your best answer would have to be c

hoped this helped lol have a good day

6 0
2 years ago
Read 2 more answers
Pleaseee help!!! If you can, answer both :))
kherson [118]
Okay the first one is what u did lol
6 0
2 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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2 years ago
The expression 1000(1.1)t represents the value of a $1000 investment that earns 10% interest per year, compounded annually for t
melamori03 [73]
1000(1.1)4
multiply the numbers
$4400
3 0
2 years ago
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