Answer:


And the confidence interval for the difference is between:

Step-by-step explanation:
We have the following info given:
sample mean for medium Pizzas from Prim's
sample mean for medium Pizzas from Pizza Place
sample deviation for Prim's
sample deviation for Pizza Palca
sample size selected for each case
The confidence interval for the difference of means is given by:

And for the 95% confidence we need a significance level of
and
, the degrees of freedom are given by:

And the critical value would be

And replacing we got:


And the confidence interval for the difference is between:

(y - 0.18y) * 1.08
Just explain what each part of it means and try to make it seem long.
Answer:
(A)
Step-by-step explanation:
Point A is at (-2,4)
Rule of a 180° rotation about the origin: (x,y) --> (-x,-y)
Using the rule, (-2,4) will become (2,-4).
A' should be (2,-4) or Option A.
Answer:
Here we have given two catogaries as degree holder and non degree holder.
So here we have to test the hypothesis that,
H0 : p1 = p2 Vs H1 : p1 not= p2
where p1 is population proportion of degree holder.
p2 is population proportion of non degree holder.
Assume alpha = level of significance = 5% = 0.05
The test is two tailed.
Here test statistic follows standard normal distribution.
The test statistic is,
Z = (p1^ - p2^) / SE
where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]
p1^ = x1/n1
p2^ = x2/n2
p^ = (x1+x2) / (n1+n2)
This we can done in TI_83 calculator.
steps :
STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER
Test statistic Z = 1.60
P-value = 0.1090
P-value > alpha
Fail to reject H0 or accept H0 at 5% level of significance.
Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.