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Anastaziya [24]

1 year ago

13

F(5)= 12 for geometric sequence that is defined recursively by the formula f(n) = 0.3* f(n-1), where n is an integer and n is gr

eater than 0. Find f(7). Round your answer by the nearest hundredth

1 answer:

svet-max [94.6K]1 year ago

7 0

The value of f(7) is 1.08

<em><u>Solution:</u></em>

Given that,

$f(5) = 12$

<em><u>The sequence is defined recursively by formula:</u></em>

$f(n) = 0.3 \times f(n-1)$

where n is an integer and n is greater than 0

<em><u>Substitute n = 6 in given formula,</u></em>

$f(6) = 0.3 \times f(6-1)\\\\f(6) = 0.3 \times f(5)\\\\Substitute\ f(5) = 12\\\\f(6) = 0.3 \times 12\\\\f(6) = 3.6$

<em><u>Find f(7)</u></em>

<em><u>Substitute f = 7 in given formula</u></em>

$f(7) = 0.3 \times f(7-1)\\\\f(7) = 0.3 \times f(6)\\\\f(7) = 0.3 \times 3.6\\\\f(7) = 1.08$

Thus the value of f(7) is 1.08

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Triangle PQR with vertices P(3, −6), Q(6, −9), and R(−15, 3) is dilated by a scale factor of 3 to obtain triangle P′Q′R′. Which

vovangra [49]

Answer:

Option C.

Step-by-step explanation:

The vertices of triangle PQR are P(3, −6), Q(6, −9), and R(−15, 3).

It is given that triangle PQR dilated by a scale factor of 3 to obtain triangle P′Q′R′.

We know that a figure and its image after dilation are similar. It means triangle PQR and triangle P′Q′R′

If a figure dilated by factor k about the origin then

$(x,y)\rightarrow (kx,ky)$

PQR dilated by a scale factor of 3, so

$(x,y)\rightarrow (3x,3y)$

Using this rule we get

$P(3,-6)\rightarrow P'(3(3),3(-6))=P'(9,-18)$

$Q(6,-9)\rightarrow Q'(3(6),3(-9))=Q'(18,-27)$

$R(-15,3)\rightarrow R'(3(-15),3(3))=R'(-45,9)$

The vertices of image are P'(9,-18), Q'(18,-27) and R'(-45,9).

Therefore, the correct option is C.

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2 years ago

A stone is dropped into a barrel of water and sinks to the bottom. The ball is completely covered by water. By how much does the

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Answer:

Answer: 5/12 or approx. 0.42

Step-by-step explanation:

The ball will displace as much water as its volume.

Meaning, the volume of the ball and the volume of the increase in water in the barrel will be equal.

Volume of a sphere:

$V_s=\frac{4}{3} \pi r^3$

The radius is half the diameter. The diameter of the sphere is 10, thus:

$r = d/2 = 10/2 = 5$

5^3 = 5*5*5 = 25*5 = 125

$V_s=\frac{4}{3} \pi * 5^3=\frac{4}{3} \pi * 125$

The volume of a cylinder, which will be the shape of the increase in water, is the following:

$V_c=\pi r^2 h$

We know the radius r, as we know the diameter.

$r=d/2=40/2=20$

$V_c=\pi r^2 h=\pi h * 20^2 = \pi h * 400$

We are looking for the height of the cylinder, h, as that will be the height of the water rise.

Since we know these 2 volumes are the same, we'll set them equal to each other and solve the equation:

$V_s = V_c$

$\frac{4}{3} * 125 * \pi = 400 * h * \pi$

We can get rid of pi by dividing both sides by pi:

$\frac{4}{3} * 125 = 400 * h$

And now divide both sides by 400:

$\frac{4}{3} * \frac{125}{400}= h$

Just reversing it and putting h to the left:

$h = \frac{4}{3} * \frac{125}{400} = \frac{4 * 125}{3 * 400}$

I see that I can divide both the numerator and the denominator by 4:

$h =\frac{125}{3 * 100}= \frac{125}{300}$

I'll now divide both the numerator and the denominator by 25 to simplify the expression:

$h=\frac{125}{300} =\frac{125 / 25}{300 / 25} = \frac{5}{12}$

Answer: The water rises by 5/12 (five twelfths).

If I want an approximate decimal answer, I can simply run this expression in a calculator:

$\frac{5}{12}$ ≈ $0.416666667$ ≈ $0.42$

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Answer:

Ordering a soft drink is independent of ordering a square pizza.

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20% more customers order a soft drink than pizza, therefore they cannot be intertwined.

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P(A∩B) = P(A) × P(B)

= 0.5 × .7

= 0.35

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.5 + .7 - 0.35

= 0.85

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