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ira [324]
2 years ago
13

You measure containers for international shipments. The height of the standard container is 6 feet and 7 inches. What is its hei

ght in meters?
Mathematics
1 answer:
quester [9]2 years ago
4 0

Answer:

2.042 meters hope this helps

You might be interested in
A motorboat takes 3 hours to travel 144 km going upstream. The trip takes 2 hours going downstream. What is the rate of the boat
allsm [11]
Let x be rate of boat in still water
let y be rate of current

we use this equation to relate quantities:
distance = speed · time

we have two unknowns so we might need to create a system of equationss

upstream:

speed (in km/h) = x - y
(we get speed of boat then subtract the current's speed from it since current is going against boat direction)

time = 3 hours

distance = 144 km

downstream:

speed (in hm/h) = x + y
(we get speed of boat then add the current's spd from it since current is going against boat direction)

time = 2 hours

distance = 144 km (same distance upstream and downstream)

using distance = speed times time

for upstream
144 =  3(x-y)
144 = 3x - 3y

for downstream
144 = 2(x+y)
72 = x + y

system of eqns:
144 = 3x - 3y
72 = x + y

solve by substitution: move 72 = x + y into x = 72 - y and subst into other equation for x

144 = 3(72 - y) - 3y
144 = 216 - 3y - 3y
144 = 216 - 6y
144 - 216 = -6y
-72 = -6y
y = 12 km/h

Use x = 72 - y to find x with y = 12: x = 72 - 12 = 60 km/h

rate of boat in still water is 60 km/h
rate of the current is 12 km/h
6 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
2 years ago
Read 2 more answers
The cubit is an ancient unit. Its length equals six palms. (A palm varies from 2.5 to 3.5 inches depending on the individual.) W
olasank [31]

Assuminhg the ark has a shoe-box (cuboid) shape it´s volume would be:

V_{cuboid}=lenght*width*height

We have this three measurements (l=300cubits;w=50cubits;h=30cubits)) and it can be as simple as replacing them in the equation and solving but they are in all in cubits. We will convert them to ft because the problem requires the answer in ft^{3}. In order to do this we will use the given equivalences:

1cubit=6palms\\1palm=3.10in

and another one:

1ft=12in

First we will convert from cubits to palms:

l=300cubits*\frac{6palms}{1cubit}=1800palms\\w=50cubits*\frac{6palms}{1cubit}=300palms\\h=30cubits*\frac{6palms}{1cubit}=180palms\\

now from palms to in:

l=1800palms*\frac{3.10in}{1palm}=5580in\\w=300palms*\frac{3.10in}{1palm}=930in\\h=180palms*\frac{3.10in}{1palm}=558in\\

now from in to ft:

l=5580in*\frac{1ft}{12in}=465ft\\w=930in*\frac{1ft}{12in}=77.5ft\\h=558in*\frac{1ft}{12in}=46.5ft

We can calculate the Volume now like this:

V_{ark}=465ft*77.5ft*46.5ft=1675743.75ft^{3}

The volume of trhe ark would be 1675743.75ft^{3}

6 0
2 years ago
The length of a picture frame is 6 inches more than the width. For what values of x is the perimeter of the picture frame greate
aniked [119]

Answer:

x > 36 in

Step-by-step explanation:

         Let x = the width of the picture frame.

Then x + 6 = the length of the frame.

The formula for the perimeter P of a rectangle is'

P = 2l + 2w.

So, the condition is

    2l     + 2w > 156

2(x + 6) + 2x  > 156     Distribute the 2

2x + 12 + 2x  > 156     Combine like terms

       4x + 12  > 156     Subtract 12 from each side

               4x > 144     Divide each side by 4

                x >  36

The perimeter of the picture frame will be greater than 156 in if x > 36 in.

5 0
2 years ago
30 POINTS! Monica paid sales tax of $1.50 when she bought a new bike helmet. if the sales tax rate was 5%, how much did the stor
avanturin [10]
Hmm... well, here ya go. 

1.50 ÷ 0.05 = 30 
So, the total is $30 
As for the tax rate, including the total, it would be $31.50.

Hope I helped.  
6 0
2 years ago
Read 2 more answers
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