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2 years ago

10

A hockey goalie loses 2 3/5 rating points each time his team loses. If his team loses 8 games in a row, what number represents t

he change in the goalie's rating points? in fraction

2 answers:

adelina 88 [10]2 years ago

8 0

Answer:

$20\frac{4}{5}$

Step-by-step explanation:

We have been given that a hockey goalie loses 2 3/5 rating points each time his team loses. His team loses 8 games in a row.

To find the number that will represent the change in goalie's ratings after losing 8 games we will multiply 8 by $2\frac{3}{5}$ .

$8*(2\frac{3}{5})$

Let us convert our mixed fraction into improper fraction.

$8*\frac{13}{5}$

$\frac{8*13}{5}$

$\frac{104}{5}$

$20\frac{4}{5}$

Therefore, $20\frac{4}{5}$ will represent the change in the goalie's rating points.

Vilka [71]2 years ago

3 0

Answer:-204/5

Step-by-step explanation:

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1 year ago

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Answer:

a

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

b

p-value = P(Z < -3.37 ) = 0.000376

c

There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Step-by-step explanation:

From the question we are told that

The population size is $n= 650$

The sample size for graduates is $n_1 = 300$

The sample mean for graduates is $\= x _1 = 148$

The sample standard deviation for graduates is $\sigma_1 = 16$

The sample size for under-graduates is $n _2 = 350$

The sample mean for under-graduates is $\= x _2 = 153$

The sample standard deviation for graduates is $\sigma_2 = 21$

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

Where $\mu_1 \ and \ \mu_2$ are the population mean

Now the test statistic is mathematically represented as

$t = \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} } * \sqrt{ \frac{1}{n_1} + \frac{1}{n_2} } }$

substituting values

$t = \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} } * \sqrt{ \frac{1}{300} + \frac{1}{350} } }$

$t = -3.37$

The p-values is mathematically evaluated as

p-value = P(Z < -3.37 ) = 0.000376

The above answer is gotten using a p-value calculator at (0.05) level of significance

Looking the p-value we see that it is less than the level of significance (0.05) so Null hypothesis is rejected

Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

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