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Slav-nsk [51]
2 years ago
8

Joelle plans to sell two types of balloons at her charity event: 171717‑inch latex balloons that require 222 cubic feet (\text{f

t}^3)(ft 3 )left parenthesis, f, t, start superscript, 3, end superscript, right parenthesis of helium and 181818‑inch mylar balloons that require only 0.5 \,\text{ft}^30.5ft 3 0, point, 5, space, f, t, start superscript, 3, end superscript. She only has access to 1{,}000 \,\text{ft}^31,000ft 3 1, comma, 000, space, f, t, start superscript, 3, end superscript of helium, 15\%15%15, percent of which will be unused due to pressure loss in the tanks. She wants to have at least 500500500 balloons for sale in total. For the number of latex balloons, LLL, and number of mylar balloons, MMM, which of the following systems of inequalities best represents this situation? Choose 1 answer:
Mathematics
1 answer:
zalisa [80]2 years ago
5 0
The system of inequalities would be:

L+M >= 500 (greater than or equal to)
2L + 0.5M <= 850 (less than or equal to)

The first inequality deals with the total number of balloons. She wants the total to be at least 500, so add the variables and set it greater than or equal to 500.

The second inequality deals with the helium. 2L comes from each latex balloon using 2 ft^3 of helium. 0.5M comes from each Mylar balloon using 0.5 ft^3. Together they can use no more than 85% of the 1000 ft^3 tank; 85% = 0.85; 0.85×1000=850. "No more than" tells us it must be less than or equal to.
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The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
2 years ago
The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun
Bogdan [553]

Answer:

Average rate of fall = \frac{h(3)-h(0)}{3}

Step-by-step explanation:

Since they give you an expression for the position of the object as a function of time, one can derive the average velocity of the object during the first 3 seconds of the fall by estimating the position of the object at time 0, the position of the object at time 3 seconds, finding the displacement of the object (distance covered) in that interval of time (via a subtraction of these two quantities), and finally dividing this change by the elapsed time (3 seconds) thus using the concept that velocity is the quotient between distance covered over the elapsed time:

Average rate of fall = (h(3) - h(0))/ 3

Average rate of fall = \frac{h(3)-h(0)}{3}

4 0
2 years ago
Read 2 more answers
How to solve q =r/2(s+t) for t
Lera25 [3.4K]
<span>q =r/2(s+t) for t
</span><span>2q =r(s+t) 
2q = rs + rt
rt = 2q - rs
 t = 2q/r - s
hope it helps</span>
4 0
2 years ago
6q + 9 ≤ 9 and 6q + 9 ≥ −9
Ilya [14]
Hello there!

6q + 9 ≤ 9

Start by subtracting 9 from both sides

6q + 9 - 9 ≤ 9 - 9

6q ≤ 0

Then divide both sides by 6

6q/6 ≤ 0/6

q ≤ 0

--------------

The second equation
6q + 9 ≥ -9

Start by subtracting 9 from both sides

6q + 9  - 9 ≥ -9 - 9

6q ≥ -18

Divide both sides by 6

6q/6 ≥ -18/6

q ≥ -3


Good luck with your studies!
7 0
2 years ago
Read 2 more answers
A survey found that 89% of a random sample of 1024 American adults approved of cloning endangered animals. Find the margin of er
Kobotan [32]

Answer:

The margin of error for the survey is 0.016

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1024

Sample proportion:

\hat{p} = 89\% = 0.89

We have to find the margin of error associated with a 90% Confidence interval.

Formula for margin of error:

z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

Putting the values, we get:

M.E = 1.64\times (\sqrt{\dfrac{0.89(1-0.89)}{1024}})\\\\M.E=0.016

Thus, the margin of error for the survey is 0.016

3 0
2 years ago
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