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Licemer1 [7]
2 years ago
13

Suppose a1=12−12,a2=23−13,a3=34−14,a4=45−15,a5=56−16. a) Find an explicit formula for an: . b) Determine whether the sequence is

convergent or divergent: . (Enter "convergent" or "divergent" as appropriate.)
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
4 0

I'm going to assume you meant to write fractions (because if a_n are all non-negative integers, the series would clearly diverge), so that

a_1=\dfrac12-\dfrac12

a_2=\dfrac23-\dfrac13

a_3=\dfrac34-\dfrac14

and so on.

a. If the pattern continues as above, we would have the general term

a_n=\dfrac n{n+1}-\dfrac1{n+1}=\dfrac{n-1}{n+1}

b. Note that we can write a_n as

a_n=\dfrac{n-1}{n+1}=\dfrac{n+1-2}{n+1}=1-\dfrac2{n+1}

The series diverges by comparison to the divergent series

\displaystyle\sum_{n=1}^\infty\frac1n

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Which expressions simplify to a rational answer? Select each correct answer. 29√⋅4√ 3√⋅16−−√ 73⋅−√3√ 5√⋅5√
PolarNik [594]

Answer:

The correct options are 1, 3 and 4.

Step-by-step explanation:

We need to find the expressions whose simplified form is a rational number.

Rational number: If a number is defined in the form of p/q where p and q are integers and q≠0, then it is called a rational number.

For example: 0,2, 4.3 etc.

Irrational number: If a number can not defined in the form of p/q, where p and q are integers and q≠0, then it is called an irrational number.

First expression is

2\sqrt{9}\cdot \sqrt{4}=2(3)\cdot (2)\Rightarrow 6\cdot 2=12

12 is a rational number.

Second expression is

\sqrt{3}\cdot \sqrt{16}=\sqrt{3}\cdot 4\Rightarrow 4\sqrt{3}

4\sqrt{3} is an irrational number.

Third expression is

7\sqrt{3}\cdot \sqrt{3}\Rightarrow 7\cdot 3=21

21 is a rational number.

Fourth expression is

\sqrt{5}\cdot \sqrt{5}=5

5 is a rational number.

Therefore, the correct options are 1, 3 and 4.

4 0
2 years ago
Kaylee is painting a design on the floor of a recreation room using equilateral triangles. She begins by painting the outline of
KatRina [158]
The correct answer for the given problem above would be the fourth triangle. So here is the given solution: Since Triangle 1 is already given with a measurement of 50 inches, and 80% of 50 inches if 40. Triangle 2 then is 40 inches. 80% of 40 is 32, so triangle 3 is 32 inches, and then 80% of 32 is 25.6 inches so triangle 4 is 25.6 inches. Therefore, the triangle that will first have a side length of less than 29 inches is triangle 4.
8 0
2 years ago
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Find the height of the triangular pyramid when the volume is 318 square centimeters
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2 years ago
En la escuela Francisco I. Madero de ciudad Delicias, llevaron a cabo el festejo para
REY [17]

Answer:

The number of unsold cakes was 2

Step-by-step explanation:

<u><em>The question in English is</em></u>

In the school Francisco I. Madero of Ciudad Delicias, the celebration was held for  commemorate the arrival of spring, after the parade the stalls were set up  of the kermesse. The first grade group bought 8 cakes and sold 3/4 of the total.

How much of the cake was not sold?

Let

x ----> number of cakes sold

y ----> number of cakes that didn't sell

we know that

The first grade group bought 8 cakes

so

x+y=8 -----> equation A

The first grade group sold 3/4 of the total.

so

x=\frac{3}{4}(x+y) ---> equation B

substitute equation A in equation B

x=\frac{3}{4}(8)=6

Find the value of y

6+y=8

y=2

therefore

The number of unsold cakes was 2

4 0
2 years ago
This diagram shows a pre-image △ABC , and its image, △A′′B′′C′′ , after a series of transformations.
MrMuchimi

Answer:

△ABC is first reflected across the line y=x, then reflected across the x-axis.  Since the transformations are rigid, △ABC ≅ △A''B''C''.

Step-by-step explanation:

Comparing △ABC and △A'B'C', we see that the x- and y-coordinates have been switched.  This describes a reflection across the line y=x.

Comparing △A'B'C' and △A''B''C'', we see that the y-coordinates have been negated.  This describes a reflection across the x-axis.

Reflections are called rigid transformations.  This is because they preserve congruence and shape.  Since congruence is preserved, △ABC ≅ △A''B''C''.

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