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nekit [7.7K]
1 year ago
9

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

wear a necklace. If one of the students is chosen randomly, what is the probability that this student is wearing (a) a ring or a necklace?

Mathematics
1 answer:
Reptile [31]1 year ago
7 0

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly  among the given student the probability that this student is wearing a ring or necklace is

P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1

P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

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An arc on a circle measures 250°. Within which range is the radian measure of the central angle? 0 to StartFraction pi Over 2 En
Alex Ar [27]

Answer:

The central angle is within the range π to 3π/2

Step-by-step explanation:

To convert from degrees to radians, we multiply the angle in degrees by 180/π.

To convert from radians to degree, we multiply the angle in radians by 180°/π.

π/2 = π/2 X 180°/π= 90°

π rad = π X 180°/π= 180°

3π/2 = 3π/2 X 180°/π= 270°

2π = 2π X 180°/π= 360°

Therefore the angle 250 which is between 180 and 270 is within the range :

π to 3π/2

4 0
2 years ago
Read 2 more answers
Uma urna contém 10 bolas identificadas pelas letras A, B, ..., J. Uma bola é extraída ao acaso da urna e sua letra é observada.
arlik [135]

Answer:

a) Probability that a letter of the drawn ball is vowel = (3/10) = 0.30

b) Probability that a letter of the drawn ball is consonant = (7/10) = 0.70

a) Probabilidade de uma letra da bola sacada ser vogal = (3/10) = 0.30

b) Probabilidade de uma letra da bola sacada ser consoante = (7/10) = 0,70

Step-by-step explanation:

English Translation

A ballot box contains 10 balls identified by the letters A, B, ..., J. A ball is drawn at random from the ballot box and its letter is observed. (Make the sample space and all events explicit). What is the probability that a letter of the drawn ball is: a) Vowel b) Consonant

Solution

The 10 balls are identified by A, B, C, D, E, F, G, H, I and J

Note that the probability of an event is given as the number of elements in that event divided by the number of elements in the sample space.

a) Probability of drawing a ball that has a vowel letter = P(v)

P(v) = n(v) ÷ n(S)

n(v) = Number of balls with vowel letters = 3 (that is, A, E and I)

n(S) = Total number of balls = 10

P(v) = (3/10) = 0.30

b) Probability of drawing a ball that has a consonant letter = P(c)

P(c) = n(c) ÷ n(S)

n(c) = Number of balls with consonant letters = 7 (that is, B, C, D, F, G, H and J)

n(S) = Total number of balls = 10

P(c) = (7/10) = 0.70

In Portugese/Em português

As 10 bolas são identificadas por A, B, C, D, E, F, G, H, I e J.

Observe que a probabilidade de um evento é fornecida como o número de elementos nesse evento dividido pelo número de elementos no espaço de amostra.

a) Probabilidade de desenhar uma bola com uma letra de vogal = P (v)

P (v) = n (v) ÷ n (S)

n (v) = Número de bolas com letras de vogal = 3 (ou seja, A, E e I)

n (S) = Número total de bolas = 10

P (v) = (3/10) = 0,30

b) Probabilidade de desenhar uma bola com uma letra consoante = P (c)

P (c) = n (c) ÷ n (S)

n (c) = Número de bolas com letras consoantes = 7 (ou seja, B, C, D, F, G, H e J)

n (S) = Número total de bolas = 10

P (c) = (7/10) = 0,70

Hope this Helps!!!!

Espero que isto ajude!!!!

3 0
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The grocery store is having a sale on frozen vegetables. 4 bags are being sold for $11.96. At this rate what is the cost of: 9 b
Alexandra [31]

Answer:

$26.91

Step-by-step explanation:

11.96 divided 4 = 2.99

2.99 x 9 = $26.91

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80 because wht the ratio is implying is that for every boy there is the same amount of girls
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Lucia is making a 21.6 centimeter beaded string to hang in the window. She decides to put a green bead every 0.4 centimeters and
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21.6 ÷ 0.4 = 54 times for green
21.6 ÷ 0.6 = 36 times for purple

Together, 90 beads. Separately, 54 green and 36 purple.
3 0
1 year ago
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