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2 years ago

Which value represents |7.8|?

1 answer:

8 0

Since absolute value is just taking the positive value of whatever you put in the function, it is 7.8 as well. Also, absolute value can be described as the distance from 0 on the number line. 7.8 is 7.8 "units" away from 0, thus meaning it is equal to 7.8.

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Write 0.00658 in standard form

Svetllana [295]

Answer:

0.00658 = 6.58 * 10^-3

Step-by-step explanation:

The standard form is a way of writing numbers easily in powers of 10.

To write a number in standard form, we have to move the decimal point to the front of the first non zero number.

Depending on the position of the decimal point to the first non zero number, movement can be towards the right or towards the left. When we move towards the right, our power of 10 will be negative, when we move in the left direction, our power of 10 will be positive

In this question, we shall be moving towards the right. Thus, our power of 10 is negative. We shall be moving towards the right 3 three times

Thus our power would be 10^-3

Thus our standard form will be 6.58 * 10^-3

Kindly note that another pointer is, if the value of our number to be written in standard form is less than zero, then the standard form will come in negative powers of 10. If the value of the number is greater or equal to 1 at least, then then the standard form will be in positive powers of 10

5 0

2 years ago

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

REY [17]

<span>Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

–5</span>

5 0

2 years ago

Read 2 more answers

Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12?

mario62 [17]

Answer:

The correct option is option B.

Step-by-step explanation:

The given function is

$(x - 4)^{2} - \frac{2}{3} = 6y - 12$

We can rearrange the function as

$(x - 4)^{2} - \frac{2}{3} = 6y - 12$

⇒ 3(x - 4)² - 2 = 18y - 36

⇒ 3(x - 4)² = 18y - 34

⇒ $(x - 4)^{2} = 6y - \frac{34}{3}$

⇒ $x - 4 = \pm \sqrt{6y - \frac{34}{3}}$

⇒ $x = 4 \pm \sqrt{6y - \frac{34}{3}}$

Therefore, the inverse function will be, $y = 4 \pm \sqrt{6x - \frac{34}{3}}$

Therefore, the correct option is option B. (Answer)

7 0

2 years ago

Read 2 more answers

Write and then solve for y = f(x) the differential equation for the statement: "The rate of change of y with respect to x is inv

vazorg [7]

The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4

To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
$y= \sqrt[5]{Bx+C}$ </span>

7 0

2 years ago

Rachel is bowling with her friends. her bowling ball has a radius of 4 inches. as she bowls she tracks the location of the finge

Goshia [24]

Question Continuation

The finger hole changes by 45 degrees.

Define a function, f, that gives the height of the finger hole above the ground (in inches) in terms of the angle of rotation (measured in radians) it has swept out from the 12 o'clock position.

Answer:

f(θ) = r(1 + cos(θ)) for 0 ≤ θ ≤ π/4

Step-by-step explanation:

Given

Let represent radius

r = 4 inches

Considering that she starts tracking the location when the finger hole is at the 12 o'clock; this means that the angle measurement at this point is 0°.

Let θ represent the angle

At 12 o'clock mark

θ = 0

When the finger hole changes by 45 degrees

θ = 45°

Convert 45° to radians

θ = 45° * π/180

θ = π/4

So, angle θ is such that θ∈[0, π/4]

This can be represented as

0 ≤ θ ≤ π/4

Calculating the measure of f(θ) in polar coordinates

When θ = 0, f(θ) = r (i.e. the current position of the bowl)

When θ = π/2, f(θ) = rcosθ

This is so because f(θ), being the function of the height is a measure of the radius* cos(θ)

Taking measurement of f(θ) from 0 to π/2

f(θ) = r + rcosθ

f(θ) = r(1 + cos(θ))

So, f(θ) = r(1 + cos(θ)) for 0 ≤ θ ≤ π/4

7 0

2 years ago