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grin007 [14]
2 years ago
13

When x = 3, y = 16 and when x = 6, y = 8. Which inverse variation equation can be used to model this function? y = y = 48x y = y

=
Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

y = \frac{48}{x}

Step-by-step explanation:

Inverse variation:

if y \propto \frac{1}{x}

then the equation is in the form of:

y = \frac{k}{x}                 ....[1]

where, k is the constant of variation.

As per the statement:

When x = 3, y = 16 and when x = 6, y = 8.

Substitute the value of x and y to find k.

Case 1.

When x = 3, y = 16

then;

16=\frac{k}{3}

Multiply by 3 both sides we have;

48 = k

or

k = 48

Case 2.

When x = 6, y = 8

then;

8=\frac{k}{6}

Multiply by 6 both sides we have;

48 = k

or

k = 48

In both cases, we get constant of variation(k) = 48

then the equation we get,

y = \frac{48}{x}

Therefore, the inverse variation equation can be used to model this function is, y = \frac{48}{x}

Ne4ueva [31]2 years ago
6 0
Y=48/x hope this helps you
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A poll stated that 32% of those polled think the economy is getting worse. An economist wanted to check this claim so she survey
zysi [14]

Answer:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

Step-by-step explanation:

Information given

n=750 represent the random sample taken

\hat p=0.30 estimated proportion of  people who  thought the economy is getting worse

p_o=0.32 is the value that we want to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true proportion of interest is equal to 0.32 or not.:  

Null hypothesis:p=0.32  

Alternative hypothesis:p \neq 0.32  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

8 0
2 years ago
In which set do all of the values make the inequality 2x - 1 < 10 true?
igomit [66]

2x - 1 < 10\Leftrightarrow 2x < 11\Leftrightarrow x <  \frac{11}{2}

8 0
2 years ago
In a network of 40 computers, 5 hold a copy of a particular file. Suppose that 7 computers at random fail. Let F denote the numb
anzhelika [568]

Answer:

a. E(F)=0.875

b. 99.9976%

c. P(X=2)=0.1683

Step-by-step explanation:

a. We notice that this is a binomial distribution with the probability of success;

p=\frac{5}{40}=0.125

#We are given the sample size, n=7. The Expected value is calculated as:

E(X)=np\\\\E(F)=np , n=7, p=0.125\\\\E(F)=7\times 0.125\\\\=0.875

Hence the expectation, E(F)=0.875

b. To calculate the probability of the range of F, we need to calculate all possible outcomes of F in the given sample;

P(X\leq 5)=1-P(X=6)-P(X=7)\\\\=1-{7\choose 6}(0.125)^6(1-0.125)^1-{7\choose 7}(0.125)^7(1-0.125)^0\\\\=1-0.000023365-0.000000476\\\\=0.999976158\\\\=99.9976\%

Hence, the range of F is 99.9976%

c. The probability that F=2 is calculated  using the binomial distribution function as:

P(X=2)={7\choose 2}(0.125)^2(1-0.125)^5\\\\=0.1683

Hence, the probability of F=2 is 0.1683

3 0
2 years ago
A rat is trapped in a maze. Initially he has to choose one of two directions. If he goes to the right, then he will wander aroun
Brut [27]

Answer:

The expected number of minutes the rat will be trapped in the maze is 21 minutes.

Step-by-step explanation:

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The probability of selecting any of the two directions is, \frac{1}{2}.

If the rat selects the right direction, the rat will return to the starting point after 3 minutes.

If the rat selects the left direction then the rat will leave the maze with probability \frac{1}{3} after 2 minutes. And with probability \frac{2}{3} the rat will return to the starting point after 5 minutes of wandering.

Let <em>X</em> = number of minutes the rat will be trapped in the maze.

Compute the expected value of <em>X</em> as follows:

E(X)=[(3+E(X)\times\frac{1}{2} ]+[2\times\frac{1}{6} ]+[(5+E(X)\times\frac{2}{6} ]\\E(X)=\frac{3}{2} +\frac{E(X)}{2}+\frac{1}{3}+\frac{5}{3} +\frac{E(X)}{3} \\E(X)-\frac{E(X)}{2}-\frac{E(X)}{3}=\frac{3}{2} +\frac{1}{3}+\frac{5}{3} \\\frac{6E(X)-3E(X)-2E(X)}{6}=\frac{9+2+10}{6}\\\frac{E(X)}{6}=\frac{21}{6}\\E(X)=21

Thus, the expected number of minutes the rat will be trapped in the maze is 21 minutes.

3 0
2 years ago
If m (RQ = 118°,<br><br> then ∠T =<br><br> 59<br> 118<br> 336
baherus [9]

angle T would be half the arc length of RQ

 118/2 = 59

 angle T = 59 degrees

8 0
2 years ago
Read 2 more answers
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