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katrin [286]
2 years ago
11

There were females and males present at the high school pep rally. Find the ratio of males to the total number of people present

. Express as a simplified ratio.

Mathematics
1 answer:
Softa [21]2 years ago
8 0

Answer:  4:9

Step-by-step explanation:

The complete question is provide in the attachment below.

Given, Number of females = 125

Number of males = 100

Total people = 120+100=225

Now, the ratio of males to the total number of people present = \dfrac{\text{Total number of males}}{\text{Total people}}

=\dfrac{100}{225}

Divide numerator and denominator by 25 , we get

Ratio of males to the total number of people present =\dfrac{4}{9}

Hence, the ratio of males to the total number of people present =  4:9

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in a certain class, 22 pupils take one or more of chemistry, economic, government. 12 take economic (E), 8 take government (G) a
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Answer:

ai) n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) see attachment

bi) n(C⋂G) = x = 1

bii) n(G) only = 3

Step-by-step explanation:

Let chemistry = C

Economic = E

Government = G

n(E) = 12

n(G) = 8

n(C) = 7

ai) number of pupils for economics and chemistry = 0

number of pupils for economics and government = 4

The set notation for both:

n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) find attached the Venn diagram

bi) n(C⋂G) = ?

Let number of n(C⋂G) = x

From the Venn diagram

n(C) only = 12-4 = 8

n(G) only = 8-(4+x) = 4-x

n(E) only = 7-x

n(E⋂C⋂G) = 0

n(E⋂C) = 0

n(E⋂G) = 4

Total: 8+ 4-x + 7-x + x + 0+0+4 = 22

23 -x = 22

23-22 = x

x = 1

n(C⋂G) = x = 1

Number of pupils that take both chemistry and government = 1

(bii) government only = n(G) only = 4-x

n(G) only = 4-1 = 3

Number of students that take government only = 3

8 0
1 year ago
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