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aksik [14]
2 years ago
14

Ella completed the following work to test the equivalence of two expressions. '

Mathematics
1 answer:
Romashka [77]2 years ago
8 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

<u>Equivalent algebraic expressions </u> are those expressions which on simplification give the same resulting<u> expression.</u>

Two algebraic <u>expressions</u> are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

3f+2.6=3.1+2.6=3+2.6=5.6

2f +2.6=2.1+2.6=2+2.6=4.6

5.6≠   4.6

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

3f+2.6=2f+2.6

3f=2f

3f-2f=0

f=0

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

this what i know

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hichkok12 [17]

Answer:

BD = 4.99 units

Step-by-step explanation:

Consider the triangle ABD only.

The angle formed is 31 degrees which occurs between two sides that are AD and BC.

We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.

Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD

Using formula for tanθ

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2 years ago
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Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

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In whatever way we find reference angles,

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Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos.  Hence these options cannot be for reference angles.

III option is (-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )

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ie reference angle of orignal angle t = 180+t

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7 0
1 year ago
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If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'? 
Vlad1618 [11]

Consider triangle XYZ with vertices at points X(1,-3), Y(3,0) and Z(-1,-1). If triangle XYZ is reflected across the line y = 1, then the rule of reflection is

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Answer: See explanation

Step-by-step explanation:

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