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2 years ago

PLEASE HELP ME!

2 answers:

5 0

Thicknesses at different point are: 41, 38, 36, 29, 34, 44, 46, 43, 35, 40

In increasing order: 29, 34, 35, 36, 38, 40, 41, 43, 44, 46

Median = (38+40)/2 = 39m

Median thickness is 39m

nasty-shy [4]2 years ago

3 0

Answer:

Median=39m

Step-by-step explanation:

It is given that the data set is in the form of the 10 locations on the glacier, so these are:

41, 38, 36, 29, 34, 44, 46, 43, 35, 40

In order to find the estimated median thickness of the entire glacier, we need to arrange the given data set in ascending order.Thus,

29, 34, 35, 36, 38, 40, 41, 43, 44, 46

Therefore, the median is:

$M=\frac{38+40}{2}$

$M=\frac{78}{2}$

$M=39m$

Thus, the estimated median thickness of the entire glacier is 39m.

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Which score has a higher relative position, a score of 271.2 on a test for which = 240 and , or a score of 63.6 on a test for wh

Fittoniya [83]

Answer:

The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.

Step-by-step explanation:

Standardized score, z = (x - xbar)/s

xbar = mean, s = standard deviation.

For the first test, x = 271.2, xbar = 240, s = 24

z = (271.2 - 240)/24 = 1.3

For the second test, x = 63.6, xbar = 60, s = 6

z = (63.6 - 60)/6 = 0.6

The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.

Hope this Helps!!!

3 0

1 year ago

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V

Nat2105 [25]

Corrected Question

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V(5/7) represent?

Answer:

(B)the volume of the rubber ball when the radius equals five-sevenths feet

Step-by-step explanation:

The Volume of a sphere of radius r can be found using the formula:

$V(r)=\dfrac43 \pi r^3$

Therefore comparing the expression: $V(\dfrac57)$ with V(r):

$Radius, r=\dfrac57$

Thus, $V(\dfrac57)$ is the volume of a ball of radius $\dfrac57$ feet.

The correct option is B.

4 0

2 years ago

Read 2 more answers

One serving of granola provides 4% of the protein you need daily. You must get the remaining 48 grams from other sources. How ma

e-lub [12.9K]

48 grams= 96% needed

x grams. = 4%

Set up a proportion

48/96 = x/4

96/24=4
48/24=2
x=2= grams in the granola

Add the value of 96% and the value of 4% to get the value of 100%

2+48=50

Final answer: 50 grams

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2 years ago

For commission as a realtor, Michelle earns $349 plus 3% of the purchase price for each home she helps buy or sell. If she earne

Papessa [141]

Well, let us solve this step by step.

We know that Michelle earns 349 plus 3% of the Purchase price. Let us call the Purchase price as P, so that:

Earnings, E = 349 + 0.03 P

So if she earns 8,965 (E = 8,965) so we can find P:

8,965 = 349 + 0.03 P

0.03 P = 8,616

P = $287,200

8 0

2 years ago

A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un

Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, assuming a significance level 0.1

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

$H_{0}:$ p1=p2

$H_{a}:$ p1≠p2

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }$ where

p1 is the sample proportion of West University students who involved in a car accident within the past year (0.15)
p2 is the sample proportion of East University students who involved in a car accident within the past year (0.12)

p is the pool proportion of p1 and p2 ( $\frac{15+12}{100+100}=0.135$ )
n1 is the sample size of the students from West University (100)
n2 is the sample size ofthe students from East University (100)

Then we have z= $\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } }$ ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

Assuming significance level 0.1, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0

2 years ago