Ask question

Ask question

All categories

2 years ago

6

On a Friday evening a pizza shop had orders for 4 pepperoni, 97, and 335 cheese pizzas. If the 4 cooks each made an equal number

of pizzas, how many pizzas did each cook make?
SHOW YOUR WORK

2 answers:

aksik [14]2 years ago

5 0

Add the order of pizzas together and divide by four. Round your answer.

Karo-lina-s [1.5K]2 years ago

5 0

Add the order of pizzas together and divide by 4 round your answer .

You might be interested in

A small island is 4 miles from the nearest point P on the straight shoreline of a large lake. If a woman on the island can row a

True [87]

Answer:

a) t(x) = [ √ (4)² + (x)²]/ 4 + 7/5 - x/5

b) x = 0,97 miles

c) t (min) = 1,24 hours

Step-by-step explanation: See Annex

Figure in annex shows a clear description of the situation

Let x be distance in miles between point P and where boat lands

A woman has to row a distance L

L = √ (4)² + (x)²

and the part to get to the town (which she has to walk)

d = ( 7 - x)

But we are required to give time as a function of x

distance = speed * time ⇒ t = distance / speed

Therefore

t(x) = [ √ (4)² + (x)²]/ 4 + ( 7 - x ) / 5

t(x) = [ √ (4)² + (x)²]/ 4 + 7/5 - x/5

Taking derivatives both sides of the equation

t¨(x) = ( 2x)*4 / 16√ (4)² + (x)²] - 5/25

t¨(x) = x/ 2√ (4)² + (x)²] - 1/5

t¨(x) = 0 x/ 2√ (4)² + (x)²] - 1/5 = 0

[ 5 x - 2√ (4)² + (x)²] = 0 ⇒ 5x = 2√ (4)² + (x)²] or

25 x² = 4 ( 4 + x²)

25 x² = 16 + 8x²

17x² = 16

x² = 16/17

x² = 0,941

x = 0,97 miles

And the distance walking to get to town

d = 7 - x d = 7 - 0,97

d = 6,03 miles

The least travel time is t(x) = [ √ (4)² + (x)²]/ 4 + 7/5 - x/5

t (min) = √ 16 + 0,94) /4 + 1,4 - 0,97/5

t (min) = 1,03 + 1,4 - 0,194

t (min) = 1,24 hours

7 0

2 years ago

NEED HELP ASAP!!!!!

katen-ka-za [31]

If restaurant rotates $60^{0}$ every 15 minutes, then after one hour it will rotate $60^{0}*4=240^{0}$ .
When restaurant makes full rotation $360^{0}$ , the length will be $2 \pi r=2 \pi *80=160\pi$ . But $240^{0}$ <span>is only $\frac{2}{3}$ from the full rotation, so the bird will pass $160\pi * \frac{2}{3} =335$ ft
</span><span>
</span><span>Answer: B is a correct choice
</span>

8 0

2 years ago

Stephanie is a very good soccer player. She can kick a soccer ball with an initial velocity of

marshall27 [118]

H(x)=−4.9x2+21.3x? we want to know what x is when the ball hits the ground well when the ball hits the ground the height between the ball and the ground is 0 so you want to solve for x when h(x)=0

5 0

2 years ago

Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that $p = 0.2$

20 drivers

This means that $n = 20$

a. at most 6 will come to a complete stop?

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115$

$P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576$

$P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369$

$P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054$

$P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182$

$P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746$

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133$

91.33% probability that at most 6 will come to a complete stop

b. Exactly 6 will come to a complete stop?

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

10.91% probability that exactly 6 will come to a complete stop.

c. At least 6 will come to a complete stop?

Either less than 6 will come to a complete stop, or at least 6 will. The sum of the probabilities of these events is decimal 1. So

$P(X < 6) + P(X \geq 6) = 1$

We want $P(X \geq 6)$ . So

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 = 0.8042$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8042 = 0.1958$

19.58% probability that at least 6 will come to a complete stop

d. How many of the next 20 drivers do you expect to come to a complete stop?

The expected value of the binomial distribution is

$E(X) = np = 20*0.2 = 4$

4 of the next 20 drivers do you expect to come to a complete stop

4 0

2 years ago

Which is a true statement about the line x − 4y = 8?

Vedmedyk [2.9K]

The y-intercept of the line is (0, -2), the x-intercept is (8, 0). the slope of the line is in fact 1/4

so your answer is C.

hope this helps, God bless!

8 0

2 years ago