Answer:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
88% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)
Answer:
The expected number of tests, E(X) = 6.00
Step-by-step explanation:
Let us denote the number of tests required by X.
In the case of 5 individuals, the possible value of x are 1, if no one has the disease, and 6, if at least one person has the disease.
To find the probability that no one has the disease, we will consider the fact that the selection is independent. Thus, only one test is necessary.
Case 1: P(X=1) = [P (not infected)]⁵
= (0.15 - 0.1)⁵
P(X=1) = 3.125*10⁻⁷
Case 2: P(X=6) = 1- P(X=1)
= 1 - (1 - 0.1)⁵
P(X=6) = (1 - 3.125*10⁻⁷) = 0.999999
P(X=6) = 1.0
We can then use the previously determined values to compute the expected number of tests.
E(X) = ∑x.P(X=x)
= (1).(3.125*10⁻⁷) + 6.(1.0)
E(X) = E(X) = 6.00
Therefore, the expected number of tests, E(X) = 6.00
The volume of a cylinder can be calculated by multiplying the area of its base times the height. It is calculated as follows:
V = πr²h
V = π(8/2)²(20)
V = 1005.31 cm³
Therefore, the correct answer is option 1. Hope this answers the question. Have a nice day.
Answer:
The answer is 72 degrees
Step-by-step explanation:
The picture that Helpmetnx showed does work. But they made a mistake and assumed that the diagonal is a angle bisector, and it's not.
1. rectangle ABCD, BD & AC are the diagonals. ∠ABD =36 degrees
2. ∠ABD= ∠BDC = 36 - alternate interior angles
3. ∠DBC = 90 - 36 = 54. ∠DBC =∠ADB = ∠BCA = 54
4. Now we know that the triangle formed between the two diagonals is a isosceles triangle because of base angle theorem.
5. 180 - 54*2 = 72 degrees
I hope this helps!
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content…
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side.
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day.
