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ICE Princess25 [194]
2 years ago
6

Which graph is represented by the piecewise function? f(x) = {−3xx−1x<0x≥1 Question 11 options: A) image B) image C) image D)

image
Mathematics
1 answer:
hodyreva [135]2 years ago
3 0
Where are the images?
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A student walks 1/4 Mile from her home to the store on her way to a friend's house at the store is one third of the wave to her
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Her friend's house is 1/12 miles away from her house.

Since 1/4 miles is 1/3 of the way, 1/4 x 1/3 = 1/12.
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Given that d is the midpoint of line segment ab and k is the midpoint of line segment bc, which statement must be true? (May giv
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B is the midpoint of line segment AC

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What is the cricket’s hang time (amount of time the cricket is airborne)? Round to the nearest thousandth h(t) = –16t2 + 14t
Stels [109]
We have that
h(t) = –16t²<span> + 14t
using a graph tool
see the attached figure

</span><span>the cricket’s hang time is the difference  between point (0,0) and (0.875,0)
</span>(0.875-0)=0.875 sec

the answer is 0.875 sec

8 0
2 years ago
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To go on the class trip, chang needs at least $125. he has saved $45, and he makes $7 an hour at his job. what is the minimum nu
Murljashka [212]
The total amount that Chang will received from his wages is the product of his hourly wage times the number of hours he has worked (n). His total savings should not be less than $125. The equation that best describes the situation is, 
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Solving for n in the inequality gives an answer of n≥11.42 hours. Thus, he needs to work for at least 12 hours.
6 0
1 year ago
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g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0
1 year ago
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