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Feliz [49]
2 years ago
5

Assuming two hikers begin at a trail start, which scenarios must be true based on the table? Check all that apply.

Mathematics
2 answers:
Basile [38]2 years ago
6 0

Answer:

A,b,d just did this problem on edgenuity

Step-by-step explanation:

Brilliant_brown [7]2 years ago
5 0
We need to see the table in order to answer the question
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I need to find both of the solutions to the equation 100+(n-2)^ = 149
rodikova [14]

Answer:

Step-by-step explanation:

hello :

100+(n-2)² = 149

100-100+(n-2)² = 149-100

(n-2)² = 49  

(n-2)² - 49  =0    but 49=7²

(n-2)² - 7²  =0   use identity : a²-b²=(a-b)(a+b)

(n-2-7)(n-2+7)=0

(n-9)(n+5)=0

n-9=0 or n+5=0

n=9 or n=-5

                                             

5 0
2 years ago
A rectangular exercise mat has a perimeter of 36 feet. The length of the mat is twice the width. Write and solve an equation to
Karo-lina-s [1.5K]
<h2>Hello!</h2>

The answers are:

- Length

length=2width=12feet

- Width

width=6feet

- Area

Area=72feet^{2}

<h2>Why?</h2>

We are given the perimeter of a rectangular mat, and we are asked to find the area, and write an equation to determine the length, if feet, of the mat. To solve this problem we need to remember the equation of the perimeter of a rectangle, which is:

Perimeter=2length+2width

Using the given information we have,

36feet=2length+2width

Also, we know that the length is twice the width, so:

length=2width

Then, substituting the second equation into the first equation, we can find the width of the mat.

Substituting, we have:

36feet=2(2width)+2width

36feet=4width+2width

36feet=6width

[tex]\frac{36feet}{6} =width\\width=\frac{36feet}{6} =6feet[/tex]

Then, substituting the width into the second equation, we can find the length of the mat,

Substituting, we have:

length=2width

length=2(6feet)=12feet

Then, finding the area, we have:

A=length*width=12feet*6feet=72feet^{2}

Have a nice day!

7 0
2 years ago
For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
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Times 3 plus 2.5 is the pattern, and the next number is 383.5
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