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Iteru [2.4K]
1 year ago
10

On January 1st 2020 the populations of Japan and the Philippines were 126.5million and 109.6 respectively. Japan's population is

currently decreasing by 0.2% per year while the population of the Philippines is increasing by 1.6% per year. If these rates of change remain constant, during which year will the two population be the same​
Mathematics
1 answer:
Elza [17]1 year ago
8 0
Well that will happen I’m not sure I think 2040
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Which of the following is the expansion of (3c + d2)6?
vovangra [49]

Answer: Option A) 729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12} is the correct expansion.

Explanation:

on applying binomial theorem,  (a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r

Here a=3c, b=d^2 and n=6,

Thus, (3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r

⇒ (3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6

⇒(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}

⇒(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}

⇒(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}

3 0
2 years ago
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When comparing functions, such as Seth’s scenarios for travelling to school, will the function with the greatest initial value c
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Answer:

It will depend whether is function time dependent or not.

Step-by-step explanation:

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1 year ago
Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

4 0
2 years ago
Someone explain and help pls
jasenka [17]
Your answer for the girls in the gymnastics club is correct.

Do the percentage of water the same way:  Divide 139 by 197.
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