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Iteru [2.4K]
2 years ago
10

On January 1st 2020 the populations of Japan and the Philippines were 126.5million and 109.6 respectively. Japan's population is

currently decreasing by 0.2% per year while the population of the Philippines is increasing by 1.6% per year. If these rates of change remain constant, during which year will the two population be the same​
Mathematics
1 answer:
Elza [17]2 years ago
8 0
Well that will happen I’m not sure I think 2040
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A wall in Marcus's bedroom is 8 2/5 feet high and 16 2/3 feet long If he paints 1/2 of the wall blue, how many square feet will
Alja [10]
We can simplify across between the 5 and the 50 and also between the 42 and the 3.
8 0
2 years ago
Read 2 more answers
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
2 years ago
if 1000 spherical of radius 1 cm are melted to form a bigger bulb. Then find the radius of bigger bulb​
never [62]

Answer:

10 cm

Step-by-step explanation:

Given:

No. of small spherical bulb = 1,000

radius (r) of smaller bulbs = 1 cm

Required:

radius of the bigger bulb

SOLUTION:

The following equation represents the relationship of the volume of the smaller and bigger bulb,

\frac{V_2}{V_1} = 1,000

Where,

V_2 = volume of bigger bulb

V_1 = volume of smaller bulb

1,000 is the number of smaller bulbs melted to form the bigger bulb.

Volume of a sphere is given as, ⁴/3πr³

Therefore:

V_2 = ⁴/3*π*r³ = 4πr³/3

V_1 = ⁴/3*πr³ = ⁴/3*π*(1)³ = ⁴/3π*1 = 4π/3

Plug the above values into the equation below:

\frac{V_2}{V_1} = 1,000

\frac{\frac{4*pie*r^3}{3}}{\frac{4*pie}{3}} = 1,000

\frac{4*pie*r^3}{3}*{\frac{3}{4*pie} = 1,000

\frac{4*pie*r^3*3}{3*4*pie} = 1,000

\frac{12*pie*r^3}{12*pie} = 1,000

r^3 = 1,000 (12pie cancels 12 pie)

r = 10 (taking the cube root of each side)

Radius of the bigger bulb = 10 cm

3 0
2 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Bumek [7]

Answer:

x+178x=2000 cans

Step-by-step explanation:

Hope this Helped

3 0
2 years ago
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5} 
The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
2 years ago
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