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konstantin123 [22]
1 year ago
6

A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree. How tall is the tree?

Mathematics
1 answer:
Eddi Din [679]1 year ago
5 0

Given:

A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree.

To find:

The length of the tree.

Solution:

A bird was sitting 16 feet from the base of an oak tree.

Vertical distance between bird and base = 16 feet

Then the bird flew 20 feet to reach the top of the tree.

Now, the vertical distance between bird and base = (16+20) feet

So, length of the oak tree is it the sum of 16 feet and 20 feet.

\text{Length of the oak tree}=16+20 feet

\text{Length of the oak tree}=36 feet

Therefore, the length of the oak tree is 36 feet.

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Yan is climbing down a ladder. Each time he descends 4 rungs on the ladder, he stops to see how much farther he has to go. If Ya
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Answer:not A

Step-by-step explanation:

8 0
1 year ago
The following table shows the number of hours a cleaning company spends cleaning apartments.
mart [117]
First, plot the points in a graph to see the general trend. The independent variable is time. I used MS Excel to plot the points in a graph, as shown in the attached picture.

1. The relationship is linear as shown in the general trend.
2. The relationship presents that as time increases, the number of apartments cleaned also increases. The two variables are directly proportional.
3. The rate of change represents the slope of the line. Choose any two points and find the slope. 

m = (6-3)/(2-1) = 3 apartments cleaned/hour

7 0
2 years ago
The population of Smalltown in the year 1890 was 6,250. Since then, it has increased at a rate of 3.75% each year. • What was th
Vikki [24]

Answer:

  • year 1915 :   15,689
  • year 1940 :  39,381

t = 137.9 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t  

Where:

p = original population

r = growing rate (decimal form)

t= years

A = population after t years

Replacing with the values given:

A = 6,250 (1 + 3.75/100)^t

A = 6,250 (1 + 0.0375)^t

A = 6,250 (1.0375)^t

  • So, by the year 1915 :

1915-1890 = 25 years passed (t)

A = 6,250 (1.0375)^25

A = 15,689

  • by the year 1940 :

1940-1890 = 50 years passed (t)

A = 6,250 (1.0375)^50

A = 39,381

  • When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.

1,000,000= 6,250 (1.0375)^t

1,000,000/ 6,250 =(1.0375)^t

160 = 1.0375^t

log 160 = log 1.0375^t

log 160 = (t ) log 1.0375

log160 / log 1.0375= t

t = 137.9 years

8 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
2 years ago
The length of a picture frame is 6 inches more than the width. For what values of x is the perimeter of the picture frame greate
aniked [119]

Answer:

x > 36 in

Step-by-step explanation:

         Let x = the width of the picture frame.

Then x + 6 = the length of the frame.

The formula for the perimeter P of a rectangle is'

P = 2l + 2w.

So, the condition is

    2l     + 2w > 156

2(x + 6) + 2x  > 156     Distribute the 2

2x + 12 + 2x  > 156     Combine like terms

       4x + 12  > 156     Subtract 12 from each side

               4x > 144     Divide each side by 4

                x >  36

The perimeter of the picture frame will be greater than 156 in if x > 36 in.

5 0
2 years ago
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