We can create a parabola equation of the trajectory using
the vertex form:
y = a (x – h)^2 + k
The center is at h and k, where h and k are the points at
the maximum height so:
h = 250
k = 120
Therefore:
y = a (x – 250)^2
+ 120
At the initial point, x = 0, y = 0, so we can solve for
a:
0 = a (0 – 250)^2 + 120
0 = a (62,500) + 120
a = -0.00192
So the whole equation is:
y = -0.00192 (x – 250)^2 + 120
So find for y when the golf ball is above the tree, x =
400:
y = -0.00192 (400 - 250)^2 + 120
y = 76.8 ft
So the ball cleared the tree by:
76.8 ft – 60 ft = 16.8 ft
Answer:
16.8 ft
Answer:
The number of dogs that had both Lyme disease and arthritis is 18
Step-by-step explanation:
Let x represent dogs that have both Lyme disease and arthritis
Dog with only Lyme disease = 42 - x
Dog with only arthritis = 96 - x
The sum of the 3 category should give 120
x + (42 - x) + (96 - x) = 120
Collect like terms and solve
x - x - x + 42 + 96 = 120
-x + 138 = 120
138 - 120 = x
x = 18
Dog with only Lyme disease = 42 - x = 42 - 18 = 24
Dog with only arthritis = 96 - x = 96 - 18 = 78
Therefore, the number of dogs with both Lyme disease and anthritis is 18.
Answer:
- 5.8206 cm
- 10.528 cm
- 23.056 cm^2
Step-by-step explanation:
(a) The Law of Sines can be used to find BD.
BD/sin(48°) = BD/sin(50°)
BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm
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(b) We can use the Law of Cosines to find AD.
AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°
AD^2 ≈ 110.841
AD ≈ √110.841 ≈ 10.5281 . . . cm
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(c) The area of ∆ABD can be found using the formula ...
A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°
A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2
_____
Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.
Answer:
The ratio of the areas = the ratio of the squares of the scale factor.
So the area of Z is 3^2 * 11 = 99 sq units.
You gotta move that b to the side ya digg
