2 years ago

T(m)=0.04m+1.26?? I don't understand how to solve it...

Mathematics

1 answer:

Marat540 [252]2 years ago

3 0

You gotta move that b to the side ya digg

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A sumo wrestling ring is circular and has a circumference of 4.6\pi \text{ meters}4.6π meters4, point, 6, pi, start text, space,

frez [133]

Answer:

The area of the sumo wrestling ring is $5.29 \pi$

Step-by-step explanation:

The circumference of the circular sumo wrestling ring is $4.6\pi$ , that means its radius $r$ is:

$2\pi r=4.6\pi$

$r=\frac{4.6}{2} =\boxed{2.3\:meters.}$

Now once we have the radius $r$ of the sumo wrestling ring we can find its area $A$ by the following formula:

$A=\pi r^2$

Putting in the value of $r=2.3\:meters$ we get:

$A=\pi (2.3m)^2=\boxed{5.29\pi\:\:m^2}$

Therefore the area of the sumo wrestling ring is ${5.29\pi\:\:m^2$

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2 years ago

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F is between e and g, EF=7 and FG=6. find EG

irina [24]

------- (EF)
------ (FG)
------ + ------- =
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2 years ago

For a certain type of copper wire, it is knownthat, on the average, 1.5 flaws occur per millimeter.Assuming that the number of f

mario62 [17]

Answer:

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 1.1156 occur / millimeters

Step-by-step explanation:

Step 1:-

Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.

by Poisson random variable given that λ = 1.5 flaws/millimeter

Poisson distribution $P(X= r) = \frac{e^{-\alpha } \alpha ^{r} }{r!}$

Step 2:-

The probability that no flaws occur in a certain portion of wire

$P(X= 0) = \frac{e^{-1.5 } \(1.5) ^{0} }{0!}$

On simplification we get

P(x=0) = 0.223 flaws occur / millimeters

Conclusion:-

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters

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The 12 oz

Step-by-step explanation:

The twelve ounce because if you buys two of them its 2.18 and youll have four more ounces for only 19 more cents than the 20oz

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