What is the volume of a sphere with a diameter of 43.5 cm, rounded to the nearest tenth of a cubic centimeter?
1 answer:
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Inscribe triangle RST in the square with dimensions 4×4, as shown in the figure.
from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.
so
units squared
similarly,
units squared
Thus, the areas are equal.
from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.
so
similarly,
Thus, the areas are equal.
Answer:
The standard deviation on the critical path = 0.834
Step-by-step explanation:
Variance of activity A () = 0.33
Variance of activity B () = 0.67
Variance of activity C () = 0.33
Variance of activity D () = 0.17
Thus the standard deviation on the critical path () =
+
+
+
=
+
+
+
= 0.6956
= 0.834
The standard deviation on the critical path = 0.834