313.75 I believe that is the correct answer or som
Answer:
a) 60%
Step-by-step explanation:
This problem can be solved through binomial probability
Let's say probability of success is the probability of absent
p = 5% = 0.05
Probability of failure
q = 1-p = 0.95
The number of trial in this case is the number of employees randomly selected
n = 10
Since we are looking for 0 absent employee, we are looking for the probability that the success is nil (i.e 0)
x = 0
Binomial therorem
B(n,x,p) = B(10,0,0.05)
= C(10,0) * p^x * q^(n-x)
= 1 * (0.05^0) * (0.95^10)
= 1 * 1 * 0.95^10
= 0.59873693923
= 0.6 or 60%
Answer: the boy won 10 games
Step-by-step explanation:
Let's call B as the number of games won by the boy, and F as the number of games won by the father.
We know that, there is a total of 26 games:
B + F = 26.
We know that in each game won by the boy, he wins 8 cents, for every game that the father wins, the boy losses 5 cents, and we know that at the end of the 26 games, the boy did not win or lose any money, so we have:
B*8 + F*(-5) = 0.
Then we have a system of equations:
B + F = 26
8*B - 5*F = 0.
The first step is isolating one of the variables. Let's start isolating F in the first equation:
B + F = 26
F = 26 - B.
Now we can replace this in the second equation:
8*B - 5*F = 0
8*B - 5*(26 - B) = 0
8*B + 5*B - 5*26 = 0
13*B = 5*26
B = 5*26/13 = 5*2 = 10
So the boy won 10 games (then the father won the other 16 games)
Answer:
65 i think
Step-by-step explanation:
Answer:
(nearest tenth)
Step-by-step explanation:
Given:
G(-2, -3)
H(0, 3)
Required:
Distance between point G and H = GH
Solution:
Distance between G(-2, -3) and H(0, 3):
Let,
(nearest tenth)
