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2 years ago

A grapefruit has a peel that is 1cm thick and a total diameter of 12cm. What percentage of volume of the grapefruit is the peel?

Mathematics

1 answer:

ira [324]2 years ago

4 0

Answer:

0.3056 or 30.56%

Step-by-step explanation:

The volume of the grapefruit with the peel is:

$V_p=\frac{4 \pi (d/2)^2}{3}\\V_p=\frac{4 \pi (12/2)^2}{3}\\V_p=48 \pi$

When removing the peel, the grapefruit diameter becomes 10 cm (take out 1 cm of peel from each side). The volume of the grapefruit without the peel is:

$V_n=\frac{4 \pi (d/2)^2}{3}\\V_n=\frac{4 \pi (10/2)^2}{3}\\V_n=33.333 \pi$

The percentage of the volume correspondent to the peel is given by the difference between both volumes, divided by the total volume:

$\%P = \frac{48\pi - 33.333\pi}{48\pi}\\ \%P =0.3056 = 30.56\%$

30.56% of volume of the grapefruit is the peel.

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Answer:

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Step-by-step explanation.

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1 year ago

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olasank [31]

We have the expression:
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Then, we will get rid of the brackets as follows:
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Now, we will gather the like terms and add them as follows:
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1 year ago

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1 year ago

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Yuliya22 [10]

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Let's plug in the given cos(t) value:
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And solve sin(t):
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Lana71 [14]

Answer:

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Step-by-step explanation:

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