Answer:
the probability is 0.1143
Step-by-step explanation:
here are the details from the question you asked
number of people = 6
nuber of weapons = 6
number of rooms = 9
after narrowing it down to
3 people,3 weapons, and 6 rooms
= ⁶C₃ * ⁶C₃ *⁹C₆ / ²¹C₁₂
= 20 * 20 * 84 / 293930
= 33600/293930
= 0.1143
<u>The probability of making a random guess of the person who is guilty, weapon and location from this choices that have been narrowed down and the guess being correct is 0.1143</u>
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
Answer:
Step-by-step explanation:
Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.
if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes
8000 = 7250,000/x + 60
8000 - 60 = 7250000/x
7940 = 7250000/x
7940x = 7250000
x = 7250000/ 7940
x = 913 ft^2
Answer:
Option B
Step-by-step explanation:
Options for the given question -
A.
A histogram
B.
A cumulative frequency table
C.
A pie chart
D.
A frequency polygon
Solution
Option B is correct
The data represents the frequency value for a given interval and hence it represents the cumulative form of frequency distribution.
