Answer:
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Step-by-step explanation:
(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)
(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)
−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
<span> a=2.5b-11, c=1.5b+1, and a=c so
2.5b-11=1.5b+1
b=12 so a=19 and c=19
so a+b+c=50 </span>
Number > 5 - round up
Number = 5 - round up
Number < 5 - round and keep the number the same
7526.442
Hundredth = 2nd decimal place = 4
2 < 5
Round and keep the number the same
7526.44
Answer:
The fraction jumped into boiling water because it wanted to be reduced.
Step-by-step explanation:
This is a maths riddle about fractions. We often see fractions that we might feel could be reduced. So, if these kinds of fractions jumps into a boiling water, they get reduced. The riddle is rather funny though.
