Question

Rewrite the expression (3a^2b^3c^5)/(8x^4y^3z)so that it has no denominator. (note: do not use a fraction line in your answer. also, use ' ' for multiplication between numbers. )

Answer 1

Use:

$\dfrac{1}{a}=a^{-1}\\\\\dfrac{1}{a^n}=a^{-n}$

$\dfrac{3a^2b^3c^5}{8x^4y^3z}=3a^2b^3c^5\cdot8^{-1}x^{-4}y^{-3}z^{-1}$

Answer: 3"8^-1a^2b^3c^5x^-4y^-3z^-1

Answer 2

Answer : The expression will be,

$3\times a^2\times b^3\times c^5\times 8^{-1}\times x^{-4}\times y^{-3}\times z^{-1}$

Step-by-step explanation :

As we are given that the expression:

$(3a^2b^3c^5)/(8x^4y^3z)$

Using exponent law :

$\frac{1}{x^a}=x^{-a}$

If we move denominator to numerator write minus sign with the exponent.

So, the expression will be:

$(3\times a^2\times b^3\times c^5)\times (8^{-1}\times x^{-4}\times y^{-3}\times z^{-1})$

or,

$3\times a^2\times b^3\times c^5\times 8^{-1}\times x^{-4}\times y^{-3}\times z^{-1}$