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1 year ago

23^0 is equal to _____. 0 1 1/23 23

Mathematics

2 answers:

miv72 [106K]1 year ago

7 0

Answer:

the answer is 1

Step-by-step explanation:

Aliun [14]1 year ago

5 0

Answer:

Step-by-step explanation:

Anything to the power is 0 is equal to 1.

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Triangular numbers can be represented with equilateral triangles formed by dots. The first five triangular numbers are 1, 3, 6,

Novosadov [1.4K]

Position in the sequence triangular number relation

1 1 1 = 1*(1+1)/2

2 3 3 = 2(2+1)/2

3 6 6 = 3(3+1)/2

4 10 10 = 4(4+1)/2

5 15 15= 5(5+1)/2

Call n the position in the sequence, then the triangular number is: n(n+1)/2

7 0

2 years ago

Read 3 more answers

Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v

Bumek [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

is dimensionally consistent

is not dimensionally consistent

is dimensionally consistent

is not dimensionally consistent

is dimensionally consistent

is not dimensionally consistent

Step-by-step explanation:

From the question we are told that

The equation are

$A) \ \ a^3 = \frac{x^2 v}{t^5}$

$B) \ \ x = t$

$C \ \ \ v = \frac{x^2}{at^3}$

$D \ \ \ xa^2 = \frac{x^2v}{t^4}$

$E \ \ \ x = vt+ \frac{vt^2}{2}$

$F \ \ \ x = 3vt$

$G \ \ \ v = 5at$

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$

Generally in dimension

x - length is represented as L

t - time is represented as T

m = mass is represented as M

Considering A

$a^3 = (\frac{L}{T^2} )^3 = L^3\cdot T^{-6}$

and $\frac{x^2v}{t^5 } = \frac{L^2 L T^{-1}}{T^5} = L^3 \cdot T^{-6}$

Hence

$a^3 = \frac{x^2 v}{t^5}$ is dimensionally consistent

Considering B

$x = L$

and

$t = T$

Hence

$x = t$ is not dimensionally consistent

Considering C

$v = LT^{-1}$

and

$\frac{x^2 }{at^3} = \frac{L^2}{LT^{-2} T^{3}} = LT^{-1}$

Hence

$v = \frac{x^2}{at^3}$ is dimensionally consistent

Considering D

$xa^2 = L(LT^{-2})^2 = L^3T^{-4}$

and

$\frac{x^2v}{t^4} = \frac{L^2(LT^{-1})}{ T^5} = L^3 T^{-5}$

Hence

$xa^2 = \frac{x^2v}{t^4}$ is not dimensionally consistent

Considering E

$x = L$

;

$vt = LT^{-1} T = L$

and

$\frac{vt^2}{2} = LT^{-1}T^{2} = LT$

Hence

$E \ \ \ x = vt+ \frac{vt^2}{2}$ is not dimensionally consistent

Considering F

$x = L$

and

$3vt = LT^{-1}T = L$ Note in dimensional analysis numbers are

not considered

Hence

$F \ \ \ x = 3vt$ is dimensionally consistent

Considering G

$v = LT^{-1}$

and

$at = LT^{-2}T = LT^{-1}$

Hence

$G \ \ \ v = 5at$ is dimensionally consistent

Considering H

$a = LT^{-2}$

$\frac{v}{t} = \frac{LT^{-1}}{T} = LT^{-2}$

and

$\frac{xv^2}{2} = L(LT^{-1})^2 = L^3T^{-2}$

Hence

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$ is not dimensionally consistent

8 0

2 years ago

Un guardia forestal divisa, desde un punto de observación A, un incendio en la dirección N27° 10’ E. Otro guardia, que se encuen

Inga [223]

Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

$\dfrac{sin \ F}{f} = \dfrac{sin \ A }{a}$

$\dfrac{sIn \ 79}{6} = \dfrac{sin \ 63}{a}$

a sin 79 = 6 sin 63

$a =\dfrac{6 \times sin \ 63}{sin \ 79}$

$a =\dfrac{6 \times 0.8910}{0.9816}$

a = 5.446 millas

la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)

$\dfrac{sin \ F}{f} = \dfrac{sin \ B}{b}$

$\dfrac{sin \ 79}{6} = \dfrac{sin \ 38}{b}$

b sin 79 = 6 sin 38

$b = \dfrac{6 \times sin \ 38}{sin \ 79}$

$b = \dfrac{6 \times0.6157 }{0.9816}$

b = 3.7635 millas

la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

8 0

1 year ago

If Emily made 75% of the baskets that she attempted if she made nine baskets how many attempt did she make

kvasek [131]

Twelve attempts were made at making a basket

6 0

1 year ago

8,000 is blank as 800

Alecsey [184]

8,000 is 10 times as much as 800

3 0

2 years ago

Read 2 more answers