A hackberry tree has roots that reach a depth of

Mathematics

1 answer:

Degger [83]2 years ago

5 0

Answer:

24.6967 meters

Step-by-step explanation:

The roots of the tree go 6 and 5 over 12 meters below the ground level.

Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.

Again the top of the tree is 18.28 meters high from the ground level.

Therefore, the total height of the tree from the bottom of the root to the top is

(6.4167 +18.28) = 24.6967 meters (Answer)

You might be interested in

Negative 120 divided by 15

madreJ [45]

-120 ÷ 15 = -8.

Hope this helps.

8 0

1 year ago

Read 2 more answers

Which transformation causes the described change in the graph of the function y = cos x?

tia_tia [17]

A: a horizontal shrink would be caused by cos 3x.
B: a vertical stretch would be caused by 3 cos x
C: a horizontal stretch would be caused by cos (1/3)x
D: a vertical shrink would be caused by 1/3 cos x.

4 0

2 years ago

Read 2 more answers

a model car is one tenth of the size of the real car the models measures 42cm longs what the length of length of the real car

trapecia [35]

Just multiply 42 by 10 and that gives you 420 , so the real car has a length of 420cm or 4.2 metres :)

8 0

2 years ago

Read 2 more answers

What is the following product? (StartRoot 12 EndRoot + StartRoot 6 EndRoot) (StartRoot 6 EndRoot minus StartRoot 10 EndRoot)

Crank

Answer:

The product results in: $6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}$ , which agrees with answer A of the given choices.

Step-by-step explanation:

We need to apply distributive property for the product of two expressions each consisting of two terms, and also use the properties of products of radicals of the same root:

$(\sqrt{12} +\sqrt{6} )(\sqrt{6} -\sqrt{10} )=\\=\sqrt{12*6} -\sqrt{12*10} +\sqrt{6*6} -\sqrt{6*10} =\\=\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60}$