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umka21 [38]
2 years ago
13

A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular

area. The area that is inside the circle, but outside the gazebo, requires mulch. This area is represented by the function m(x), where x is the length of the radius of the circle in feet. The homeowner estimates that he will pay $1.50 per square foot of mulch. This cost is represented by the function g(m), where m is the area requiring mulch. Which expression represents the cost of the mulch based on the radius of the circle?

Mathematics
3 answers:
Nikolay [14]2 years ago
5 0

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2} (AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2}x^{2}(2 sin 22.5° cos 22.5°)

= \frac{1}{2}x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

= 2.828 x^{2}

Area required for mulch = circular area - area of the gazebo

= 3.14x^{2} -2.828x^{2}

= 0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312 x^{2} × 1.5

= 0.468 x^{2}

Hence, total cost g(m) = 0.468 x^{2}.

Guest1 year ago
0 1

bitchassnigga

Guest
1 year ago
bitttttttchhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiitttttttttttttttttttttttttttcccccccccccccccccccccccccccchhhhhhhhhhhhhhhhhhhhhhhhhhhhbbbbbbbbbbbbbbbbbbbbbbbbbiiiiiiiiiiiiiiiiiiiiiiiitttttttttttttttttttttttttttccccccccccccccccccccccccccccccchhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
Guest1 year ago
0 0

A) is the answer

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Answer:

G = (9.4, 9,4)

Step-by-step explanation:

The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH

x-distance:

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11/5 = 2.2

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Point G = Point F + (2.2*2, 1.2*2)

Point G = (5, 7) + (4.4, 2.4)

= (9.4, 9.4)

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1 year ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
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For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

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For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

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6 0
2 years ago
Read 2 more answers
g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the
blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean amount of money spent on textbooks = $121.60

            \sigma = population standard deviation = $6.36

            n = sample of students = 36

            \mu = population mean

<em>Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>

<em />

So, 95% confidence interval for the population mean, \mu is ;

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                      of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                      = [ 121.60-1.645 \times {\frac{6.36}{\sqrt{36} } } , 121.60+1.645 \times {\frac{6.36}{\sqrt{36} } } ]

                                      = [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0
2 years ago
A scientist is studying tulips and daffodils. The scientist estimates that there are 150 tulips in the population of 600 tulips
Flauer [41]

Answer:  Last Option is correct.

Step-by-step explanation:

Since we have given that

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Number of tulips = 150

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So, We can get the ratio of tulips to daffodils which is given by

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1) He can choose 50 flowers.

As there are 1:3 of tulip and daffodils flowers but if we divide 50 by 4 it will give a decimal number, so it can't represent the required thing.

2) He can choose 25 tulips and 25 daffodils

As they are divided into 1:1 so, it can't represent the 1:3 tulip to daffodils population.

3) He can choose 15 tulips and 60 daffodils

As it is divided into 1:4 inspite of 1:3.So it can't represent the required population.

4) He can choose 10 tulips and 30 daffodils.

So, Last option which states that he can choose 10 tulips and 30 daffodils as in this case the ratio of tulips to daffodils is 1:3.

Hence, Last Option is correct.

4 0
1 year ago
Read 2 more answers
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