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lbvjy [14]
2 years ago
11

Given triangle GHJ, the measure of angle G equals 110°, the measure of angle J equals 40°, and the measure of angle H equals 30°

. Complete the following statements.
Since angle G is
angle, the opposite side, JH, is
.

The order of the side lengths from longest to shortest is
Mathematics
1 answer:
Trava [24]2 years ago
8 0

Given:

In triangle GHJ, ∠G = 110°, ∠J = 40° and ∠H = 30°.

To find:

The answer to complete the given statements.

Solution:

According to triangle side and angle relationship, largest angle has longest opposite side and smallest angle has shortest opposite side.

∠G = 110°, ∠J = 40° and ∠H = 30°.

Here, ∠G > ∠J = 40° and  ∠G > ∠H. So,  ∠G is the Largest angle.

Since angle G is  largest angle, the opposite side, JH, is  longest.

Clearly,

110° > 40° > 30°.

∠G >  ∠J  > ∠H

Using triangle side and angle relationship, we get

JH > GH > GJ

The order of the side lengths from longest to shortest is JH, GH ahd GJ.

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2 years ago
Consider the following problem: A farmer with 950 ft of fencing wants to enclose a rectangular area and then divide it into four
Alina [70]

Answer:

Step-by-step explanation:

(a)

Suppose we came up with an ideology whereby we pick a value for the length including the length dividing the inside into 4 parts(5 parallel sides), then we can get the value for breath by using the following process.

Let assume the length of the rectangle is 50;

Then, the breath can be calculated as follows:

= 50 × 5 = 250   ( since the breath is divided into 5 parallel sides)

The fencing is said to be 950 ft

So, 950 - 250 = 700

Then divided by 2, we get:

= 700/2

= 350

So for the first diagram; the length = 50 and the breath = 350

The area = 50 × 350 = 17500 ft²

Now, let's go up a little bit.

If the length increase to 100;

Then 100 × 5 = 500

⇒ 950 - 500 = 450

⇒ 450/2 = 225

The area = 225 × 100 = 22500 ft²

Suppose the length increases to 150

Then 150 × 5 = 750

⇒ 950 - 750 = 200

⇒ 200/2 = 100

The area = 150 × 100 = 15000 ft²

The diagrams for each of the outline above can be seen in the image attached below.

(b) The diagram illustrating the general solution can be seen in the second image provided below.

(c) The expression for  the total area A in terms of both x and y is:

Area A = x×y

(d) Recall that:

The fencing is said to be 950 ft.

And the length is divided inside into 5 parallel sides;

Then:

5x + 2y = 950  (from the illustration in the second image below)

2y  = 950 - 5x

y = \dfrac{950}{2} - \dfrac{5}{2}x

y = 475- \dfrac{5}{2}x

(e)

From (c); replace the value of y in (d) into (c)

Then:

Area A = x×y

f(x)= x\times ( 475 -\dfrac{5}{2}x)

Open brackets

f(x)= ( 475 x-\dfrac{5}{2}x^2)

(f)

By differentiating what we have in (e)

f(x)= ( 475 x-\dfrac{5}{2}x^2)

f'(x)= ( 475 (1)-\dfrac{5}{2}(2x))

f'(x)= 475 -5x

\implies  475 = 5x

x = 475/5

x = 95

From (d):

y = 475- \dfrac{5}{2}x

y = 475- \dfrac{5}{2}(95)

y =237.5

∴

Area A = x × y

Area A = 95 × 237.5

Area A = 22562.5 ft²

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The rectangular playground in tim's school is three times as long as it is wide. the area of the playground is 75 square meters.
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300-297+294-291+288-285+...+6-3
vladimir2022 [97]
300 - 297 = 3

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