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2 years ago

8

gil owns a life insurance policy that he purchased when he first graduated college it has a 100000 death benefit and gil pays pr

emiums for it every month out of his checking account the insurance

2 answers:

Scorpion4ik [409]2 years ago

7 0

The insurance Gil has is most likely individual life insurance.

Kaylis [27]2 years ago

4 0

Answer:

Individual life insurance

Step-by-step explanation:

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Amira sells balloon animals. She uses the same number of balloons for each animal she makes. The table compares the number of ba

Vikki [24]

Answer:

4 balloons for each balloon animal.

Step-by-step explanation:

Amira sells balloon animals. The given table compares the number of balloon animals sold and the remaining number of balloons on a certain day.

Animals Balloons

15 200

24 164

33 128

When she sold 15 animals the leftover balloons were 200.

then she sold 24 animals the number of leftover balloons were 164.

The difference of the number of items = 24 - 15 = 9 more animals sold

The difference of the leftover balloons = 200 - 164 = 36 balloons used

Now the number of her sold animals was = 33

and the left over balloons = 128

The number of sale was increased by 24 to 33 = 33 - 24 = 9 more animals

and the leftover balloons now 164 to 128 = 164 - 128 = 36 used

Therefore, we can see each sale of 9 balloon animals she used 36 balloons.

so Amira used for each balloon animal = $\frac{36}{9}$

= 4 balloons.

Amira used 4 balloons for each balloon animal.

5 0

2 years ago

Read 2 more answers

Three students solve a challenge math problem. Every day, the number of students who solve the problem doubles. There are 384 st

attashe74 [19]

OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.

So we have 3 kids and it doubles

Day 1 : 6

Day 2 : 12

Day 3 : 24

Day 4 : 48

Day 5 : 96

Day 6 : 192

Day 7: 384

So it should take 7 days or a week to solve all the problems.

The equation:

(3 * 2)^x = 384

8 0

2 years ago

Read 2 more answers

PLEASE HELP! Given the following equation of an exponential function N= 40.25(1.0394)^t determine the base, b, of the exponentia

NeTakaya

The exponential equation in its generic form is:
y = A * (b) ^ t
Where,
A: initial amount
b: base (Growth rate for b> 1. Decrease rate for b <1.)
t: time.
We have then that the equation is:
N = 40.25 (1.0394) ^ t
The base is:
b = 1.0394> 1 (it is a growth rate)
Answer:
The base, b, of the exponential model is:
b = 1.0394
the base is a growth rate

5 0

2 years ago

What input value produces the same output value for the two functions on the graph ?

Andrej [43]

we know that

The intersection point of both graphs is a common point for both functions, for which for the same input value, both functions will have the same output value.

so

the point of intersection is $(4,3)$

for an input value equal to $4$

the output value for both functions is $3$

therefore

<u>the answer is the option</u>

X= 4

4 0

2 years ago

Read 2 more answers

Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How

mixer [17]

To solve this, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial investment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year

For the first 4 years we know that: $P=2350$ , $r= \frac{4.2}{100} =0.042$ , $t=4$ , and since the problem is not specifying how often the interest is communed, we are going to assume it is compounded annually; therefore, $n=1$ . Lest replace those values in our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2350(1+ \frac{0.042}{1} )^{(1)(4)}$
$A=2350(1+0.042)^{4}$
$A=2770.38$

Now, for the next 6 years the intial investment will be the final amount from our previous step, so $P=2770.38$ . We also know that: $r= \frac{4.9}{100} =0.049$ , $t=6$ , and $n=1$ . Lets replace those values in our formula one more time:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2770.38(1+ \frac{0.049}{1})^{(1)(6)$
$A=2770.38(1+0.049)^6$
$A=3691.41$

We can conclude that Collin will have <span>£3691.41 in his account after 10 years.</span>

4 0

2 years ago