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Alexxx [7]
2 years ago
6

Morgan is walking her dog on an 8-meter-long leash. She is currently 500 meters from her house, so the maximum and minimum dista

nces that the dog may be from the house can be found using the equation |x – 500| = 8. What are the minimum and maximum distances that Morgan’s dog may be from the house?
Mathematics
2 answers:
Nonamiya [84]2 years ago
7 0

Answer:

its c

Step-by-step explanation:

lara31 [8.8K]2 years ago
3 0
<u>The minimum distance is 492 meters from the house (500 - 8 = 492), and the maximum distance is 508 meters from the house (500 + 8 = 508). The dog may be slightly closer to the house, depending on how long the dog is, or if Morgan is using a leash extender.</u>
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How many ways can Rudy choose 4 pizza toppings from a menu of 14 toppings if each topping can only be chosen once
madam [21]

Answer:

24,024

Step-by-step explanation:

Calculation for How many ways can Rudy choose 4 pizza toppings from a menu of 14 toppings

The 4 pizza toppings from a menu of 14 toppings will be 14,13,12,11

Hence,

14*13*12*11=24,024

Therefore the numbers of way Rudy can choose 4 pizza toppings from a menu of 14 is 24,024

6 0
2 years ago
Jane invested £4000 for 3 years with an interest rate of 1.5%. What was her investment worth at the end of this period?
ddd [48]

Answer:

$4182.7

Step-by-step explanation:= 4000*(1.5%)*3

Year 1= 4000*(100%+1.5%)= 4060

Year 2= 4060*(100%+1.5%)= 4120.9

Year 3= 4120.9*(100%+1.5%)= 4182.7

6 0
2 years ago
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Can someone help me with this
Anvisha [2.4K]

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D. \frac{{7}^{11} }{ {4}^{11} }

Step-by-step explanation:

( \frac{7}{4}) {}^{11} = \frac{7 {}^{11} }{4 {}^{11} }

Since we are multiplying an exponential number to a fraction the answer is going to be

\frac{7 {}^{11} }{4 {}^{11} }

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7 0
2 years ago
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Which number line represents the solution of 4x - 9 ≥ -21? what would the number line look like ?
Fittoniya [83]

Solve for x:

4x-9 >= -21

Add 9 to both sides:

4x >= -12

Divide both sides by 4:

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The number line would have a solid dot on -3 with a line and arrow pointing to the right of -3

5 0
2 years ago
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(1 point) If f(t) is continuous for t≥0, the {\it Laplace transform} of f is the function F defined by F(s)=∫[infinity]0f(t)e−st
QveST [7]

Answer:

The Laplace transform of f(t) = 1 is given by

F(s) = (1/s) for all s>0

Step-by-step explanation:

Laplace transform of a function f(t) is given as

F(s) = ∫∞₀ f(t) e⁻ˢᵗ dt

Find the Laplace transform for when f(t) = 1

F(s) = ∫∞₀ 1.e⁻ˢᵗ dt

F(s) = ∫∞₀ e⁻ˢᵗ dt = (1/s) [-e⁻ˢᵗ]∞₀

= -(1/s) [1/eˢᵗ]∞₀

Note that e^(∞) = ∞

F(s) = -(1/s) [(1/∞) - (1/e⁰)]

Note that (1/∞) = 0

F(s) = -(1/s) [0 - 1] = -(1/s) (-1) = (1/s)

Hope this Helps!!!

8 0
2 years ago
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