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Tatiana [17]
2 years ago
12

A home builder wants 5 5 acres of land split into 13 13 equal sections. Three of these expressions give the number of acres of l

and each home will have. Which one does NOT?
Mathematics
2 answers:
kolezko [41]2 years ago
6 0

Answer:

the answer is 13 divided by 5

Step-by-step explanation:

stepladder [879]2 years ago
4 0

Answer:

Check Explanation

Step-by-step explanation:

The options to be examined for the wrong one isn't presented, and it wasn't obtainable online, So, I'll exhaustively cover all the common possible answers!

5 acres of land. Acres is a unit of measurement that is most pecuilar to land. It is basically expressing the area of the land.

So, if 5 acres of land is to be divided into 13 sections with equal areas.

Each of the 13 land areas will have an area of (5/13) = 0.385 acre

1 acre = 4046.856 m²

5 acres = 20,234.28 m²

Each of the 13 land areas will have an area of (20234.28/13) = 1556.5 m²

1 acre = 43560 ft²

5 acres = 5 × 43560 = 217,800 ft²

Each of the 13 land areas will have an area of (217800/13) = 16,753.85 ft²

1 acre = 0.00156 square miles

5 acres = 5 × 0.00156 = 0.0078 square miles

Each of the 13 land areas will have an area of (0.0078/13) = 0.0006 square miles.

So, basically, whatever units one converts the area to, just divide the value by 13 and one obtains the area of each of the 13 portions of land that makes up the 5 acres.

Hope this Helps!!!

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Answer:

4

Step-by-step explanation:

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Two square rooms have a total floor area of 89m2. One room is 3m longer each way than the other. Find the dimensions of the two
Rudiy27

Answer:

A

Step-by-step explanation:

Let the smaller room have an area of x^2

Let the larger room have an area of (x + 3)^2

(x+3) ^2 + x^2 = 89               Be careful not to make it 89^2.

x^2 + 6x + 9 + x^2 = 89        Expand the binomial squared

2x^2 + 6x + 9 - 89 = 0          Subtract 89 from both sides

2x^2 + 6x + 9 - 89 = 0          Combine

2x^2 + 6x - 90=0                  Divide by 2

x^2 + 3x - 45 = 0         This factors.

(x + 9)(x- 5) = 0

X + 9 gives nothing useful

x - 5 = 0

x = 5

x + 3 = 5+3 = 8

So the answer is A

3 0
2 years ago
The graph of f(x) shown below resembles the graph of g(x)=x^3, but it has been vertically stretched. Which of the following coul
Deffense [45]

Answer: it’s b

Step-by-step explanation:

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2 years ago
What is log Subscript 15 Baseline 2 cubed rewritten using the power property?
nalin [4]

Answer:

The equivalent expression

Step-by-step explanation:

Assuming your expression is \log_{15}2^3, then we can use the power property of logarithm , which is \log_ab^n=n\log_ab.

If we let a=15, b=2, and n=3

Then using the power property of logarithm will give us:

\log_{15}2^3=3\log_{15}2

Using the power property of logarithm, the equivalent expression is 3\log_{15}2

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How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?
o-na [289]

Answer:

2500 numbers

Step-by-step explanation:

Problem;

 Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

 Let us approach this in a step wise manner;

  5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;  

  the first number divisible by 45 within this range is 10035

   the last number divisible by 45 in this range is 99990

    increment is 45

The total number in this range is:

           \frac{last number - first number}{increment}  + 1  = \frac{99990 - 10035}{45}  + 1

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To solve this problem, let us find the number of digits that are divisible by 60;  

  the first number divisible by 60 within this range is 10020

   the last number divisible by  in this range is 99960

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\frac{99990 - 10080 }{90}

The total number in this range is:

               \frac{last number - first number}{increment}  + 1  = \frac{99960 - 10020}{60}  + 1  

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To solve this problem, let us find the number of digits that are divisible by 90;  

  the first number divisible by 90 within this range is 10080

   the last number divisible by  in this range is 99990

    increment is 90

The total number in this range is:

         \frac{last number - first number}{increment} + 1  = \frac{99990 - 10080}{90} + 1

                                                  = 1000 numbers

Now solution:

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                                        = 2500 numbers

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