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Ghella [55]
2 years ago
5

Arthur took out a 20 year loan for $60,000 at an APR of 4.4% compounded monthly. Approximately how munch would save if he paid i

t off 3 years early Apex A. $4516.32,B. $1129.08,C. $376.36,D.$877.96
Mathematics
2 answers:
Eduardwww [97]2 years ago
8 0
Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}

Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid

For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36

Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30

For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22

Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98

The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32

Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
Arte-miy333 [17]2 years ago
7 0
It's $877.96 on APEX, taking the quiz currently.
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bogdanovich [222]

Answer:

Option A 50-page photo album holds 400 photographs.

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

step 1

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For the point (3,24)

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k=y/x

k=24/3=8

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y=8x

step 2

<em>Verify each statement</em>

case A) 50-page photo album holds 400 photographs.

For x=50

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y=8(50)=400 -----> is correct

case B) 80-page photo album holds 560 photographs.

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y=8(80)=640 -----> is not correct

case C) 100-page photo album holds 8,000 photographs.

For x=100

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y=8(100)=800 -----> is not correct

case D) 900-page photo album holds 8,400 photographs.

For x=900

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y=8(900)=7,200 -----> is not correct

9 0
2 years ago
Read 2 more answers
Bonzo went to a carnival. At the first
Shalnov [3]

Bonzo started with 2.1 dollars

Step-by-step explanation:

Assume that Bonzo has $x

1. Change $x to cents

2. Calculate the remaining money with him after each game

3. Equate the left money in the 3rd game by zero to find x

∵ $1 = 100 cents

∴ $x = 100 x cents

First game

∵ Bonzo has 100 x cents

∵ He paid 10¢ to get in

∴ The money left is (100 x - 10)

∵ He spent half  the money he had left

- That mean the money left with him is the other have

∴ The money left with him = \frac{1}{2} (100 x - 10) = (50 x - 5) cents

∵ He spent 10¢  to get out

∴ The money left after 1st game = (50 x - 5) - 10

∴ The money left after 1st game = (50 x - 15) cents

Second game

∵ Bonzo has (50 x - 15) cents

∵ He paid 10¢ to get in

∴ The money left is (50 x - 15) - 10 = (50 x - 25)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (50 x - 25) = (25 x - 12.5) cents

∵ He spent 10¢  to get out

∴ The money left after 2nd game = (25 x - 12.5) - 10

∴ The money left after 2nd game = (25 x - 22.5) cents

Third game

∵ Bonzo has (25 x - 22.5) cents

∵ He paid 10¢ to get in

∴ The money left is (25 x - 22.5) - 10 = (25 x - 32.5)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (25 x - 32.5) = (12.5 x - 16.25) cents

∵ He spent 10¢  to get out

∴ The money left after 3rd game = (12.5 x - 16.25) - 10

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∵ He found he had no money left after the 3rd game

∴ Equate the left money with him by zero

∴ 12.5 x - 26.25 = 0

- Add 26.25 to both sides

∴ 12.5 x = 26.25

- Divide both sides by 12.5

∴ x = 2.1

<em>Bonzo started with 2.1 dollars </em>

Learn more:

You can learn more about money in  brainly.com/question/1870710

#LearnwithBrainly

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If ƒ(x ) = 3x + 1 and and ƒ -1 = , then the ordered pair of ƒ -1(10) = (10, 31) (10, 3) (3, 10)
MAXImum [283]
        f(x) = 3x + 1
           y = 3x + 1
      y - 1 = 3x + 1 - 1
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         3       3
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6 0
2 years ago
The graph of a function is shown. On a coordinate plane, a function has 2 connecting line. The first line goes from (negative 5,
Katen [24]

Answer:

f(x)=\left\{\begin{array}{l}x+3,\ \ x< 0\\ \\3,\ \ x\ge 0\end{array}\right.

Step-by-step explanation:

The graph of a function is shown in attached diagram.

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2. The equation of the right part is y = 3.

3. The expression for the function represented by the graph is

f(x)=\left\{\begin{array}{l}x+3,\ \ x< 0\\ \\3,\ \ x\ge 0\end{array}\right.

8 0
2 years ago
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