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melamori03 [73]
2 years ago
12

I need help with number 5 please

Mathematics
2 answers:
steposvetlana [31]2 years ago
7 0

Answer: Would be 55% I hope this helps!

xz_007 [3.2K]2 years ago
4 0

Answer:

55% of the actors are between the ages of 10-12.

Step-by-step explanation:

1. Add all of the frequencies

8+22+10=40

2. Divide the certain frequency by the total amount

22/40=0.55

3. Multiply by 100

0.55*100= 55%

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Maddie is reading a graph of equivalent ratios. One point on the graph is (4, 5). Maddie says (10, 8) is also on the graph. Is M
dmitriy555 [2]
Yes and no, (4, 5) multiplied by 2 is (10, 8) but reversed. It depends on how you look at it because (10, 8) would be on the other side of the graph than (8, 10) which is the actually equivalent.
6 0
2 years ago
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-6y + 3(12y) = 20(y - 1) + 15 is it true?
xxMikexx [17]

Answer:

y= - 1/2 (negative half) =  -0.5

Step-by-step explanation:

−6y+3(12y)=20(y−1)+15

Multiply 3 and 12 to get 36.

−6y+36y=20(y−1)+15

Combine −6y and 36y to get 30y.

30y=20(y−1)+15

Use the distributive property to multiply 20 by y−1.

30y=20y−20+15

Add −20 and 15 to get −5.

30y=20y−5

Subtract 20y from both sides.

30y−20y=−5

Combine 30y and −20y to get 10y.

10y=−5

Divide both sides by 10

y= -5/10

Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .

5 0
2 years ago
The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is
NeX [460]
S(t) =  -4.9t^2 + 19.6t + 24.5

when it reaches the ground s(t) = 0 


so we have -4.9t^2 + 19.6t + 24.5 = 0

solve this for t:-

-4.9(t^2 - 4t - 5) = 0

(t + 1)(t - 5) = 0

so required time t = 5 seconds  

answer 5 seconds

5 0
2 years ago
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Find the value of 3 + 5 × (2 − 1).
Alenkasestr [34]
Step 1 (simplify): 
3+5x(2-1)
8 x 1 

Step 2 (solve):
8 x 1 = 8

8 is your answer. Hope this helps :)
8 0
2 years ago
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What is a3 in an arithmetic sequence in which a10=41 and a15=61
USPshnik [31]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

thus

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and surely you know how much that is.
8 0
2 years ago
Read 2 more answers
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