The houses can be placed in 362,880 ways.
<u>Step-by-step explanation:</u>
The 9 houses are each in different design.
The each lot can place any of the 9 houses.
- The 1st lot can place anyone house of all the 9 houses.
- The 2nd lot can place one of remaining 8 houses.
- The 3rd lot can place one of remaining 7 houses.
Similarly, the process gets repeated until the last house is placed on a lot.
<u>From the above steps, it can be determined that :</u>
The number of ways to place the 9 houses in 9 lots = 9!
⇒ 9×8×7×6×5×4×3×2×1
⇒ 362880 ways.
Therefore, the houses can be placed in 362880 ways.
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
1. The total must be at least $1975:
2. Dog walks is no more than 4 times lawns:
3. At least 50 dog walks:
